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Easiest way to send output to a debug file?

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# 1  
Old 02-15-2006
Easiest way to send output to a debug file?
I have this in my script:

Code:
DEBUG_DIR=/log/rotate_output
DEBUGLOG=${DEBUG_DIR}/rotate.${TIMESTAMP}


SERVER_FILE_LIST="\
wasint0206  /logs/squid_backup
wasint0201  /logs/squid_backup"


/usr/bin/echo "${SERVER_FILE_LIST}" | while read SERVER DIRECTORY
do
    cd /log/squid_logs/${SERVER}
    rm /log/squid_logs/${SERVER}/access.log
    /usr/local/bin/scp  ${SERVER}:${DIRECTORY}/access.log.${TIMESTAMP}-12AM.gz log/squid_logs/${SERVER}
    /usr/bin/gunzip /log/squid_logs/${SERVER}/access.log.${TIMESTAMP}-12AM.gz
    /log/squid_logs/convert.sh /log/squid_logs/${SERVER}/access.log.${TIMESTAMP-12AM >> /log/squid_logs/${SERVER}/access.log.${TIMESTAMP}.convert
    /usr/bin/gzip -f /log/squid_logs/${SERVER}/access.log.${TIMESTAMP}.convert
    rm /log/squid_logs/${SERVER}/access.log.${TIMESTAMP}-12AM
done

How would I get all the output from that do loop to go to the debug file that I set up at the top? I know I could put a > ${DEBUGLOG} at the end of every line but is there an easier way to do it? Is there a way to create a dated output file from the crontab? That way the whole program could be done in one shot.
LordJezo
# 2  
Old 02-15-2006
Code:
........................

{
/usr/bin/echo "${SERVER_FILE_LIST}" | while read SERVER DIRECTORY
do
    cd /log/squid_logs/${SERVER}
    rm /log/squid_logs/${SERVER}/access.log
    /usr/local/bin/scp  ${SERVER}:${DIRECTORY}/access.log.${TIMESTAMP}-12AM.gz log/squid_logs/${SERVER}
    /usr/bin/gunzip /log/squid_logs/${SERVER}/access.log.${TIMESTAMP}-12AM.gz
    /log/squid_logs/convert.sh /log/squid_logs/${SERVER}/access.log.${TIMESTAMP-12AM >> /log/squid_logs/${SERVER}/access.log.${TIMESTAMP}.convert
    /usr/bin/gzip -f /log/squid_logs/${SERVER}/access.log.${TIMESTAMP}.convert
    rm /log/squid_logs/${SERVER}/access.log.${TIMESTAMP}-12AM
done

} > myDebugFile.txt
........................

# 3  
Old 02-17-2006
Ha.

Thanks so much.
LordJezo
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