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Need help with sed/awk command

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Top Forums Shell Programming and Scripting Need help with sed/awk command
# 15  
Old 10-21-2014
one more issue:

fields have no limit.
I mean lets say in dict1 fields are p, U
in dict2 may be T will be the field

all I mean to say is, Instead of saving field names as continuous string, dict[1].fieldName[1] = p, dict[1].fieldName[2] = U etc..
will be more unique

---------- Post updated at 12:05 PM ---------- Previous update was at 01:30 AM ----------

Can you explain this condition?
Code:
if (CNT==1 && !/^ *$/)

Last edited by linuxUser_; 10-20-2014 at 09:34 PM..
# 16  
Old 10-21-2014
Quote:
Originally Posted by linuxUser_
one more issue:

fields have no limit.
I mean lets say in dict1 fields are p, U
in dict2 may be T will be the field

all I mean to say is, Instead of saving field names as continuous string, dict[1].fieldName[1] = p, dict[1].fieldName[2] = U etc..
will be more unique
Why don't you give it a try? Every fieldname will have its own array element.
EDIT: Oh, got you now. shells don't have those structures. Recent shells with associative arrays might allow for an approach comig close...

Quote:
Can you explain this condition?
Code:
if (CNT==1 && !/^ *$/)

CNT represents the "level" of "{...}" nestings. So, if the level is 1 deep, and if there's more than an "empty" (nothing but spaces) line, print that. This is, of course, heavily depending on the structure of your file. If all the info were written in a single line, that logic would be doomed.
This User Gave Thanks to RudiC For This Post:
linuxUser_
# 17  
Old 10-21-2014
Code:
#!/bin/bash
declare -a dictName;
declare -a planeName;
declare -a fieldName;
dCount=0;
pCount=0;
fCount=0;

awk     '/^ *functions */       {F=1; next}
         F                      {CNT=CNT+gsub(/{/,"")-gsub(/}/,""); if (CNT==1 && !/^ *$/) {dictName[dCount]=$0; dCount=$((dCount+1))} }
         /fields/               {for (i=3; i<NF; i++) {fieldName[fCount]=$i; fCount=$((fCount+1))}}
         /^ *surfaces */        {S=1; next}
         S                      {gsub(/[^0-9A-Za-z]*/, ""); if (!/^ *$/) {planeName[pCount]=$i; pCount=$((pCount+1)); S=0}}
        ' file


Hi, will it work something like this?(as shown above?)

I am able to get the names wat eva I want but unable to store in a string array.
# 18  
Old 10-21-2014
I don't think that will work. You can't use shell variables inside an awk script. There is a mechanism to pass variables (cf. man awk), but you won't get back any values into variables except by command substitution. On top, you stopped using that F logical variable half way. Try like second line
Code:
!F {next}

and then, somewhere reasonable, sth containing
Code:
!CNT {exit}

This may fail if the input file structure is different from the one you presented.

You could try printing all the assignments to a file and then source that file from your shell. Or, in recent shells with "process substitution" sth like
Code:
. <(awk 'BEGIN {print "X=17"}')
echo $X
17

This User Gave Thanks to RudiC For This Post:
linuxUser_
# 19  
Old 10-21-2014
OMG... I see lot more stuffs to understand to finish this job Smilie

Can you give me a example storing a variable like this
Code:
declare -a dictName
j=0
while(some condition that satisfies my requirement-for looping)
dictName[j] <(awk '/^ *functions */       {F=1; next}
         F                      {CNT=CNT+gsub(/{/,"")-gsub(/}/,""); if (CNT==1 && !/^ *$/) {dictName[dCount]=$0; dCount=$((dCount+1))} }')

Thanks and Regards,
linuxUser_

---------- Post updated at 04:51 PM ---------- Previous update was at 04:49 PM ----------

One more thing, why is that space before the dictNames? when printing?
Can I remove that space ???
Code:
dictname[1]=[SPACE]planeDictName

# 20  
Old 10-21-2014
As I said, awk does NOT use shell variables like that, nor the $((...+1)) shell construct. As you are using bash, the process substitution might work. If
Code:
awk '                       {CNT=CNT+gsub(/{/,"")-gsub(/}/,"");
                                 if (CNT==1 && !/^ *$/) {gsub (/ /,_); print "dictname[" ++dc "]=" $0}
                                }
         /fields/               {for (i=3; i<NF; i++) print "fieldname[" ++fc "]="$i}
         /^ *surfaces */        {S=1; next}
         S                      {gsub(/[^0-9A-Za-z]*/, ""); if (!/^ *$/) {print "planename[" ++pc "]=" $0; S=0}}
        ' file

produces
Code:
dictname[1]=planeDictName
fieldname[1]=p
fieldname[2]=U
planename[1]=planeName
dictname[2]=planeDictName2
fieldname[3]=p
fieldname[4]=U
fieldname[5]=T
planename[2]=planeName

, sourcing the process substitution
Code:
. <(awk    '            {CNT=CNT+... )

will assign all those variables:
Code:
echo ${dictname[@]} ${planename[@]} ${fieldname[@]} 
planeDictName planeDictName2 planeName planeName p U p U T

But - be careful with that sourcing, as every malicious result will be executed as well!
This User Gave Thanks to RudiC For This Post:
linuxUser_
# 21  
Old 10-21-2014
in this case pwd is not working.
I want to give file name with current directory path Smilie
what to do?
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