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Bash script too many arg's

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# 1  
Old 10-15-2014
Bash script too many arg's
I have a simple bash script on RHEL that works fine when there is one file but when it finds multiple files of same condition I get too many args error.

Code:
for i in *
do
        if [ ! -f "$i" ];then
                echo "no files to move"
                exit 0
        fi
         if [ "$i" = *02.DAT ]; then
                mv $i $CD/somefolder/
        fi

# 2  
Old 10-15-2014
Its system issue whats the output of this command

Code:
getconf ARG_MAX

# 3  
Old 10-15-2014
Actually, I think this is the problem:

Code:
if [ "$i" = *02.DAT ]; then

*02.DAT does not do what you think it does here. If there's any filenames in the current folder matching it, it expands into a list of those names.

I believe you intended this:

Code:
if [[ "$i" == *02.DAT ]] ; then

double-equal in double brackets wildcards against $i instead of the current directory.
# 4  
Old 10-15-2014
you guys are great. Corona your modification has it working now. Just so I can learn something what are the extra brackets and equals doing?

Just because of my interest this is what the max is set to 2621440
# 5  
Old 10-15-2014
Another way would be:
Code:
for i in *02.DAT
do
    if [ -f "$i" ]; then
        mv -- "$i" "$CD/somefolder/"
    else
        echo "no files to move"
    fi
done

Last edited by Scrutinizer; 10-15-2014 at 03:39 PM..
This User Gave Thanks to Scrutinizer For This Post:
Kibou
# 6  
Old 10-15-2014
Some more info

Bash Pitfalls

Difference between [ and [[
# 7  
Old 10-15-2014
Actualy, with the use of *02.dat one could drop the check for its existence, as it should only be listed because it exists.
Thus it could be like:
Code:
for f in *02.dat;do mv "$f" "$CD/somefolder/"|| echo "Move failed with code: $?";done

hth
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