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For getting value between the braces

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# 1  
Old 10-14-2014
For getting value between the braces
Hi

I have a file called tmp with the content as below
Code:
more tmp
   NAMELIST(Hari)
   NAMELIST(Raju)

I want to get the values between the brackets.

When I executed the below command on zlinux I get the output which I wanted
Code:
more tmp |awk -F'[()]' '{print $2}'

But when I execute the same in the Solaris server its throwing me a blank output.

Any suggestion on what what wrong am I doing or can this be done in a different way.

Thanks
Hari M






Hari
Raju
Last edited by rbatte1; 10-15-2014 at 08:17 AM.. Reason: Added CODE tags for files
# 2  
Old 10-14-2014
More importantly on Solaris/SunOS system, change awk at the start of your script to /usr/xpg4/bin/awk or /usr/xpg6/bin/awk or nawk

--
Last edited by Akshay Hegde; 10-14-2014 at 05:36 PM..
# 3  
Old 10-14-2014
Thanks for the quick reply, nawk has worked in solaris but not in zlinux.

Is there any one format i can use which will work in both zlinux and solaris.
# 4  
Old 10-14-2014
Gnu grep
Code:
$ echo 'NAMELIST(Hari)' | grep -oP '\(\K[^)]+'
Hari


Sed
Code:
$ echo 'NAMELIST(Hari)' | sed 's/.*(\(.*\))/\1/'
Hari

Perl
Code:
$ echo 'NAMELIST(Hari)' | perl -pe 's/.*\((.*)\)/$1/'
Hari

Code:
$ echo 'NAMELIST(Hari)' | perl -lanF"[()]" -e 'print $F[1]'
Hari

Code:
$ echo 'NAMELIST(Hari)' | perl -pe 's/.*\((.+?)\).*/$1/;'
Hari


Shell
Code:
$ while IFS="()" read a b; do echo "$b"; done <<<'NAMELIST(Hari)'
Hari

For file use like this
Code:
$ while IFS="()" read a b; do echo "$b"; done <infile

Awk

Code:
$ echo 'NAMELIST(Hari)' | awk 'NR > 1 {print $1}' RS='(' FS=')'
Hari

Code:
$ echo 'NAMELIST(Hari)' | awk  'gsub(/.*\(|\).*/,"")'
Hari

Code:
$ echo 'NAMELIST(Hari)' | awk  '{split($0,A,/[()]/);  print A[2]}'
Hari

Last edited by Akshay Hegde; 10-14-2014 at 05:39 PM..
This User Gave Thanks to Akshay Hegde For This Post:
Chubler_XL
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