This can be easily mistaken after you have seen something like this
Code:
find -name "*.jpg"
which it does actually expands. The find command does not expand the same way the shell does.
There is a HUGE difference between:
Code:
find . -name "*.jpg"
and:
Code:
find . -name *.jpg
but, if there are no files with a name ending with the string ".jpg" in the directory where you invoke these commands, the results will be identical.
In the 1st case, the shell will not perform any pattern matching based on the asterisk because it is quoted. Therefore, find will receive *.jpg as an argument from the shell and find will use that argument to match against all filenames in the file hierarchy rooted in the current directory.
In the 2nd case, the shell will expand *.jpg into a list of all of the files in the current directory that match that pattern and pass one argument to find for each matched file. If there is no match, the results will be the same as if the argument had been quoted. If one filename matched, find will only look for files with the same name as the file found in the current directory in the file hierarchy rooted in the current directory. If two or more files match, you'll get a syntax error from find.
These 2 Users Gave Thanks to Don Cragun For This Post:
I have a file abc.ini and declared many variables in that file, one of the variable(DBname) value I am trying to read in my perl script but getting error.
File abc.ini content
# database name
DBname =UATBOX
my $ex_stat;
my $cmd_output;
$ex_stat = "\Qawk '/^DBname/{print... (2 Replies)
Hi,
I have an inputfile with some table names in it.
For ex:
t_arnge
t_profl
t_fac
I need a script which reads the line one by one and need to assign to some dynamic variable. If to explain the above example:
i need some
a=table_name1
table_name1=t_arnge in first time and... (4 Replies)
Hi All,
I'm writing a script to read a file line by line and then perform awk function on it. I am getting an error . My file has one name in it "James". I'm expecting my o/p to be youareJamesbond
James
./users.sh: line 7: =: command not found
#script to read file line by line
#adding... (5 Replies)
Hi,
In shell script, I have a variable var = xyz, inn, day, night, calif ....n and I would like to read them in to var1 = xzy, var2 = inn, var3= day, var4 = night....var.
probably in a loop. I would like to read the variables until end of the line. Comma is the delimiter and there's no comma at... (3 Replies)
Hi,
I am using #!/bin/sh shell. I have a variable which contains multi line data. I want to read that variable line by line. Can someone post the code to read the multi line variable line by line?
Any help is much appreciated. (2 Replies)
Hi All,
I am using SunSolaris machine.
I need to get the value of environment variable from awk begin. Then use that value as the start number of a sequence and use that in my print statement. But it is not reading the value from environment variable.
I have tried the following:
... (5 Replies)
hi,
I am using a shell script from where i will be conecting to sqlplus..
i am having a problem in passing a variable to sqlplus query..
i will be assigning the variable in the unix environment..whenever i am trying to pass a variable having the contents greater than 2500 characters, i am... (3 Replies)
Hi!
1. I have a parameter file containing path to log files. For this example both paths are the same, one is stated directly and the second using env variables.
/oracle/admin/orcl/bdump/:atlas:trc:N
${ORACLE_BASE}/admin/${ORACLE_SID}/bdump/:${ORACLE_SID}:trc:N
2. I try to parse the path... (1 Reply)
Please Help!!
Here is a very simplistic example of what I am trying to accomplish.
I need what I have inbetween the quotes to be read into the shell variable.
x="This is fun"
echo $x
The results of x from the above expression is:
This is fun
Notice the unix takes out the... (1 Reply)
I would like to prompt for input and then use it as a variable in a script.
Something like this.
#!/bin/ksh
echo "What is your name?: \c"
read response
echo "Your name is $reply" >file.txt
done
exit 0
What am I missing?
Thanks, (7 Replies)
10-10-2014
