How can I get first day of a particular month?

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10-10-2014

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How can I get first day of a particular month?

Hi,

I am new to shell scripting and I have a requirement of getting first day of specific month.

eg i need 1st day of oct 2014

Code:

 October 2014
 S  M Tu  W Th  F  S
               1  2  3   4
 5  6  7    8  9 10  11
12 13 14 15 16 17 18
19 20 21 22 23 24 25
26 27 28 29 30 31

output should be: Wed

Please suggest.

Last edited by Franklin52; 10-10-2014 at 07:29 AM.. Reason: Please use code tags

simsim90

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10-10-2014

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Did you search these fora? There should be plenty of examples / solutions to your problem... e.g. sth along this line (untested):

Code:

cal 10 | awk 'BEGIN {split ("Sun Mon Tue Wed Thu Fri Sat", DAY)} NR==3 {print DAY[8-NF]}'

RudiC

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10-10-2014

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Quote:

Originally Posted by simsim90

Hi,

I am new to shell scripting and I have a requirement of getting first day of specific month.

eg i need 1st day of oct 2014

October 2014
S M Tu W Th F S
1 2 3 4
5 6 7 8 9 10 11
12 13 14 15 16 17 18
19 20 21 22 23 24 25
26 27 28 29 30 31

output should be: Wed

Please suggest.

Hello simsim90,

Welcome to forum. Here is an example for same. Lets say we need to see month 2nd for year 1990, so here is an example for same.

Code:

cal 2 1990
   February 1990
Su Mo Tu We Th Fr Sa
             1  2  3
 4  5  6  7  8  9 10
11 12 13 14 15 16 17
18 19 20 21 22 23 24
25 26 27 28

So code to get 1st date of the month is as follows.

Code:

cal | awk 'NR==2{for(u=1;u<=NF;u++){A[++p]=$u}} NR==3 && NF<=7 {gsub(/[[:space:]]/,X,$0);val=length($0);actual_value=8-val;print A[actual_value]}'

Output will be as follows.
Th

Another example for current month(Which is October).

Code:

cal | awk 'NR==2{for(u=1;u<=NF;u++){A[++p]=$u}} NR==3 && NF<=7 {gsub(/[[:space:]]/,X,$0);val=length($0);actual_value=8-val;print A[actual_value]}'
OR
cal | awk 'NR==2{for(u=1;u<=NF;u++){A[++p]=$u}} NR==3 && NF<=7 {gsub(/[[:space:]]/,X,$0);print A[8-length($0)]}'
 
Output will be as follows.
We

Thanks,
R. Singh

Last edited by RavinderSingh13; 10-10-2014 at 07:31 AM.. Reason: Using icode instead of code for output

RavinderSingh13

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Try something like this

Script

Code:

#!/bin/bash

first_day(){ date -d "01/01/$1 + $(($2-1)) month" +"%d %B %Y %a" ;}
last_day(){  date -d "01/01/$1 + $2 month -1 day" +"%d %B %Y %a" ;}

# call function
first_day 2014 10
last_day 2014 10

first_day 2014 12
last_day 2014 12

first_day 2015 1
last_day 2015 1

Calender

Code:

[akshay@nio tmp]$ cal 10 2014
    October 2014    
Su Mo Tu We Th Fr Sa
          1  2  3  4
 5  6  7  8  9 10 11
12 13 14 15 16 17 18
19 20 21 22 23 24 25
26 27 28 29 30 31

[akshay@nio tmp]$ cal 12 2014
    December 2014   
Su Mo Tu We Th Fr Sa
    1  2  3  4  5  6
 7  8  9 10 11 12 13
14 15 16 17 18 19 20
21 22 23 24 25 26 27
28 29 30 31

[akshay@nio tmp]$ cal 1 2015
    January 2015    
Su Mo Tu We Th Fr Sa
             1  2  3
 4  5  6  7  8  9 10
11 12 13 14 15 16 17
18 19 20 21 22 23 24
25 26 27 28 29 30 31

Output

Code:

[akshay@nio tmp]$ bash date.sh
01 October 2014 Wed
31 October 2014 Fri
01 December 2014 Mon
31 December 2014 Wed
01 January 2015 Thu
31 January 2015 Sat

Akshay Hegde

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10-11-2014

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if you can use ksh93 (Korn Shell 93):

Code:

$ printf "%(%a)T\n" "first day oct 2014"
Wed
$ printf "%(%a)T\n" "first day mar 2014"
Sat

fpmurphy

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