Shell Programming and Scripting

My files:
file1 and file2 contain 157 words.
Emptyfile1 contain 0 words.

My script has to output how many files is filled with words and how many that are not.

If there are files that have words in it. It has to output "file2 and file2 contains 157 words, 0 files are empty"
If not every file is empty the output has to be "file1 and file2 contains 157 and emptyfile1, 1 file is empty"

I'm doing something wrong, can't seem to find the problem.

Code:

#!/bin/bash

while [ "$#" -gt 0 ]
do 
   if [ -s "$1" ]
   then
       wc -w "$1" "$2" "$3"
   else
        echo "there are $# that contain zero words/bytes"
   fi
   shift
done

Can you comment your script and explain what it should do ( or you expected it to do) so we can after, correct you?

yes i will

I ment what was you expecting in $# ? in $1, $2, $3 ? Or where does $# get its value etc...

$1 $2 $3 are parameters. Value: file1 file2 file3
$#: its to switch from $1 to $2 and $3 with shift. it redoes the script again for each parameter.

I got 3 files. 2 are filled with words and 1 is empty.

If there are files that have words in it. It has to output "file2 and file2 contains 157 words, 0 files are empty"
If not every file is empty the output has to be "file1 and file2 contains 157 and emptyfile1, 1 file is empty"

OK
$1 $2 $3 are positional parameters ( not mentioning $#) so you are to give them in input, but I see nowhere in your script where you read them...

Can you help me out, i'm a beginner. So its a bit difficult for me
How can i read them?