Shell Programming and Scripting

That is why I asked you what was $#...
Is that you are going to find all the files in a given directory?
And so I would use a for loop with the command ls
or using while e.g.

Code:

ls  |while  read FILE
do
   if [ -s "$FILE" ]
   then
       wc -w "$FILE"
   else
        echo "there is $FILE that contain zero words/bytes"
   fi
done

Yes its for all files in the current directory
my command should be like: ./count.sh file1.txt file2.txt emptyfile1.txt

I will try your way of doing the script.

---------- Post updated at 12:10 PM ---------- Previous update was at 11:13 AM ----------

I only want to show the given parameters.
So file1 file2 emptyfile1 has to be shown

This is my output:

Code:

157 file1.txt
157 file2.txt
29 forum.sh
there is emptyfile1.txt that contain zero words/bytes
34 count.sh
34 count.sh~

Every file in the directory is shown but i only want to output the given parameters: file1.txt file2.txt emptyfile1.txt

forum.sh is a test script
count.sh is the file counting script

Is this a homework assignment?