Shell Programming and Scripting

Hi Guys!

I am sure that this question might appeared previously, but I still don't know how to show a list of logged out users. Please help with this!

Thanks in advance

How about

Code:

cut -d: -f1 /etc/passwd

For logged out users only you can add on a pipe to omit users logged in from RudiC's command:

Code:

cut -d: -f1 /etc/passwd | grep -v "$(finger -f|awk '{print $1}')"

Note: these suggestions are incomplete if your system is also using any form of authentication other then local passwords.

yes, there is an authentication.. how to make a list in that case?

logged out means the process no longer exists. The user account does.
The number of logged out processes grows every hour.

Code:

awk -F: '{print $1} ' | while read u
do
      last $u
done

Once you see this in action you will get the idea that you need to tweak your question a bit. I'll bet what you want is everybody who logged today (or yesterday), not since the UNIX box booted up 6 weeks ago. You probably also want times/dates.

So - show us your desired output.