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awk find the first matching row

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# 1  
Old 09-29-2014
awk find the first matching row
I would like to find the first matching row and continue to search from the matching row. if column3 equal to 1 in the row, find the next matching row based on the criteria below. column3 in the matching row equal to 0 and column2 equal to column2 in the matching row



test.csv - test data
Code:
2014-09-01 00:01:30|T1|1|0|RE|Y
2014-09-01 00:03:05|T1|0
2014-09-17 23:28:13|T2|1|1|RE|N
2014-09-17 23:29:14|T2|1|0|RE|N      
2014-09-17 23:31:16|T2|0
2014-09-17 23:31:18|T2|0

expected output
Code:
 
2014-09-01 00:01:30|2014-09-01 00:03:05|T1|0|RE|Y
2014-09-17 23:28:13|2014-09-17 23:31:16|T2|0|RE|N

I have tried using the awk below, but the result is not correct.
Code:
 
awk '{if (($3=="0" && $2==B[2] && B[3]=="1"))
{print B[1], $1, B[2], B[4], B[5], B[6]; next}
{split($0,B)}}' FS=\| OFS=\| test.csv

result
Code:
 
2014-09-01 00:01:30|2014-09-01 00:03:05|T1|0|RE|Y
2014-09-17 23:29:14|2014-09-17 23:31:16|T2|0|RE|N
2014-09-17 23:29:14|2014-09-17 23:31:18|T2|0|RE|N

# 2  
Old 09-29-2014
What criteria do you want?

You have shown a program which doesn't do what you want. That's unfortunately not actually helpful in describing what you actually do want. If it was, it'd work, and you wouldn't need to ask.

I see three lines with column 3 as 1, but apparently you only want two of them? Please explain.
# 3  
Old 09-29-2014
Quote:
Originally Posted by Corona688
What criteria do you want?

You have shown a program which doesn't do what you want. That's unfortunately not actually helpful in describing what you actually do want. If it was, it'd work, and you wouldn't need to ask.

I see three lines with column 3 as 1, but apparently you only want two of them? Please explain.
Yes there are 3 lines with column3 as 1.
The matching row for the third line (2014-09-17 23:28:13|T2|1|1|RE|N) is fifth line (2014-09-17 23:31:16|T2|0).
The result will be 2014-09-17 23:28:13|2014-09-17 23:31:16|T2|0|RE|N

After that, i would like to continue to search from fifth line to find the line with column3 as 1.
# 4  
Old 09-29-2014
the description is a bit 'muddy', but see if that helps.
awk -f chail.awk myFile where chail.awk is:
Code:
BEGIN {
  FS=OFS="|"
}
$3=="1" && !($2 in f) {
   f[$2]=$0
   next
}
$3=="0" && $2 in f {
  n=split(f[$2], a, FS)
  printf("%s%c%s%c%s%c%s%c%s\n", a[1], OFS, $1, OFS, $2, OFS, $3, OFS, a[5])
}

# 5  
Old 09-29-2014
Try:
Code:
awk '$3==1 && !p{$3=$2; p=$0} $3==0 && p{n=$1; $0=p; $2=n; p=x; print}' FS=\| OFS=\| file

---
EDIT FS and OFS had fallen off.... Thenks Ravinder...
Last edited by Scrutinizer; 09-29-2014 at 01:32 PM..
This User Gave Thanks to Scrutinizer For This Post:
RavinderSingh13
# 6  
Old 09-29-2014
Quote:
Originally Posted by Scrutinizer
Try:
Code:
awk '$3==1 && !p{$3=$2; p=$0} $3==0 && p{n=$1; $0=p; $2=n; p=x; print}' file

Hello Scrutinizer,

Nice code, I think we can add FS, OFS values to same.

Code:
awk -F"|" '$3==1 && !p{$3=$2; p=$0} $3==0 && p{n=$1; $0=p; $2=n; p=x; print}' OFS="|" Input_file

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
Scrutinizer
# 7  
Old 09-29-2014
Code:
awk -F'|' '$3==1 && !a[$2] {a[$2]=$1; b[$2]=($5 OFS $6); next} $3==0 && a[$2] {print a[$2], $0, b[$2]; delete a[$2]}' OFS='|' file

Output:
Code:
2014-09-01 00:01:30|2014-09-01 00:03:05|T1|0|RE|Y
2014-09-17 23:28:13|2014-09-17 23:31:16|T2|0|RE|N
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