How to sort with ls -lh command?


 
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# 8  
Old 09-18-2014
I think the point here is the OP the listing sorted with human-readable sizes.
# 9  
Old 09-18-2014
My mistake, I missed that.

I am not in front of a solaris host at the moment but IIRC later versions of solaris du -h will display file sizes in human readable format - that will be easier to sort than ls -lh.

EDIT: Some examples:

Code:
du -k <directory>

Code:
du -m <directory>

Code:
du -g <directory>

and then sort the output.

Last edited by colshine; 09-18-2014 at 07:54 PM..
# 10  
Old 09-18-2014
That's not really sortable... K comes after G alphabetically and all.
# 11  
Old 09-19-2014
Agreed, and posting #6 matches the desired input and output
This User Gave Thanks to Chubler_XL For This Post:
# 12  
Old 09-19-2014
Quote:
Originally Posted by colshine
For ascending order try:

Code:
ls -l | sort +4n

For descending order try:

Code:
ls -l | sort +4nr

Thanks it almost works ,but when we have K and G And M
it doesn't sort numerically but alphabetically

---------- Post updated at 09:47 PM ---------- Previous update was at 09:45 PM ----------

Quote:
Originally Posted by Chubler_XL
how about this this:

Code:
ls -lh /home/sid | awk '
$9 !~/unwantedfile/{
  bytes=$5 * 1024^index("KMGTPEZY", toupper(substr($5,length($5))));
  printf "%.0f ", bytes
  print $5,$3,$6,$7,$8,$9
} ' | sort -n -r | sed 's/[^ ]* //'

You sir are a genius!! It worked perfectly !!!

If you don't ming could you explain this code. What is index and why that special word KMGTPEZY and the last sed part
# 13  
Old 09-20-2014
Index is a built-in function in awk that finds the position of a string within another.

For example index("the quick brown fox", "r") would return 12 as the first "r" found in the string is 12 characters from the front on the string.

the string KMGTPEZY represents the suffixes (Kilo, Mega, Giga, Tera, Peta, Exa, Zetta, Yotta). So index gives us 1 for K, 2 for M, 3 for G, etc. We can then raise 1024 to this number to get the conversion factor for the suffix.
# 14  
Old 09-20-2014
In addition to what Chubler_XL has already said, the entire purpose of the code:
Code:
bytes=$5 * 1024^index("KMGTPEZY", toupper(substr($5,length($5))));
  printf "%.0f ", bytes

is to undo what the ls -h option did and give you an approximation to the actual file size in bytes that can be sorted numerically. If you were willing to change the 1st command in your pipeline from ls -lh to just ls -l, those two statements could be removed from the awk script and the sed command (which deletes the file size in bytes from the output) could be removed from the end of the pipeline.
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