Shell script to find weblogic home directory


 
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# 8  
Old 09-12-2014
You need to be much more descriptive about what you are trying to do. One simple way to do what you have requested is:
Code:
echo 'jhome=/u01/app/jdk1.6.0_02'

If you are trying to modify some input that follows a certain format into a different output format, explain what your input format is and the changes to be performed to produce the output format that you want.
# 9  
Old 09-12-2014
RedHat

Hi Don,

The input format is
Code:
jhome=JAVA_HOME=/u01/app/jdk1.6.0_02

output format which we require
Code:
echo 'jhome=/u01/app/jdk1.6.0_02'

Regards,
Spgreddy
# 10  
Old 09-12-2014
Quote:
Originally Posted by spgreddy
Hi Don,

The input format is
Code:
jhome=JAVA_HOME=/u01/app/jdk1.6.0_02

output format which we require
Code:
echo 'jhome=/u01/app/jdk1.6.0_02'

Regards,
Spgreddy
The input and output you have specified are fixed strings; not formats. You have not specified what steps are to be taken to transform your input to your desired output.

A wild guess at your input format could be something like:
Code:
name1=name2=absolute_pathname

where name1 is a shell variable name consisting of only lowercase letters, name2 is a shell variable name consisting of only uppercase letters and underscore characters, and absolute_pathname is an absolute pathname containing three components in addition to the root directory and none of the components contain any whitespace characters but nay contain one or more periods (which are special in a regular expression).

Without knowing what your real input and output formats are and what transformations you are trying to perform, we can only waste our time guesing at what needs to be done to transform one fixed string into another fixed string unless we just suggest that you print the desired output string!

To get your new desired output, execute the command:
Code:
echo "echo 'jhome=/u01/app/jdk1.6.0_02'"


Last edited by Don Cragun; 09-12-2014 at 06:31 AM.. Reason: Fix typo.
# 11  
Old 09-12-2014
Hi Don,

Please find the scenario.

Code:
jhome=`grep JAVA_HOME commEnv.sh | grep jdk|sed 's/"//g'`

In the above code jhome is variable,JAVA_HOME is search pattern, commEnv.sh is file, jdk is another search pattern. When I executed the above command in the server it gives the output as

Code:
echo " jhome=$jhome"



Code:
jhome=JAVA_HOME=/u01/app/jdk1.6.0_02

mean jhome variable contains the value JAVA_HOME=/u01/app/jdk1.6.0_02.

Now my requirement is to extract /u01/app/jdk1.6.0_02 by truncating the JAVA_HOME=

so that the jhome variable value is /u01/app/jdk1.6.0_02.

Please help me how to solve this

Regards
Spgreddy

Last edited by spgreddy; 09-12-2014 at 07:05 AM..
# 12  
Old 09-12-2014
Code:
jhome=`grep JAVA_HOME commEnv.sh | grep jdk|sed 's/"//g;s/JAVA_HOME=//'`

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