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Print range of numbers

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# 1  
Old 09-08-2014
Print range of numbers
Hi

I am getting an argument which specifies the range of numbers. eg: 7-15

Is there a way that i can easily (avoiding loop) print the range of number between and including the specified above.

The above example should translate to 7,8,9,10,11,12,13,14,15
# 2  
Old 09-08-2014
Hello tostay2003,

Please use code tags while using commands and codes in your post as per forum rules. Following may help you in same.

Code:
for i in {7..15..1}
do
echo "Value of i is $i"
done

Output will be as follows.

Code:
Value of i is 7
Value of i is 8
Value of i is 9
Value of i is 10
Value of i is 11
Value of i is 12
Value of i is 13
Value of i is 14
Value of i is 15

Thanks,
R. Singh
# 3  
Old 09-08-2014
Code:
$ seq -s, 7 15

---------- Post updated at 05:40 PM ---------- Previous update was at 05:31 PM ----------

If you have the literal value 7-15 as basis and it's in a variable:
Code:
$ var=7-15
$ seq -s, `echo $var | tr '-' ' '`

# 4  
Old 09-08-2014
With recent shells with brace expansion:
Code:
var=7-15
eval echo {${var/-/..}}
7 8 9 10 11 12 13 14 15

The usual caveats for using eval apply.
This User Gave Thanks to RudiC For This Post:
jaysunn
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