Shell Programming and Scripting

HI,

I am facing an error while executing a script in for loop.

Code:

 the syntax is : for (( i=0;i<=${v_colcnt};i++ )); do
 Error : '(' unexpected

I am new to unix and have tried multiple options such as changing the script from !# /bin/ksh to !# /bin/sh (not sure if this works to execute in sh). I have tried searching for the syntax of for loop in ksh but didn't find the above syntax.Can someone please suggest if the above works in ksh.

I am using SunOS server and script is in ksh. Please help

Thanks in Advance

Moderator's Comments:

Please use code tags next time for your code and data. Thanks

Well the syntax of a for is not like that...

Code:

for i in ...
do 
   blah
   blah
   .
   .
done

First of all you have to fix the shebang/hashbang line (first line) in your script and try again.

!# /bin/ksh and !# /bin/sh <- This is wrong/invalid.

It has to be either #!/bin/ksh or #!/bin/sh

What shebang? I see nothing, but perhaps they edited the script out from under you.

for (( i=0;i<=${v_colcnt};i++ )); do looks like BASH syntax.

Hi,
Thanks for the prompt response. The hashbang syntax is

Code:

#!/bin/ksh

or

Code:

[#!/bin/sh]

only but I typed it incorrectly in my earlier post. So what I incur from the above comments is that the syntax of for is not correct for a ksh script.
I will try modifying the script using the syntax mentioned by Vbe.

Code:

 
  
 for i in [ 0- ${v_colcnt} ]
 do 
   Processing logic.
i=`expr $i+1`   .
done

are there any other options.

Thanks all for your help![/QUOTE]

Moderator's Comments:

Please use code tags for code. Not color, not font, but code, [code]stuff[/code].

Code:

[#!/bin/sh]

This is wrong, use

Code:

#!/bin/sh

That is not the syntax vbe suggested either.

There are several ways to do this, this perhaps the best for an extremely basic shell:

Code:

I=1

while [ "$I" -le "${v_colcnt}" ]
do
        ...
        let I=I+1
done