Shell Programming and Scripting

I have a number, say 174. I need to write bash code that will find the first larger number that ends in 99. That would be 199 in this case. If the number were 1263, I would be looking for 1299, for 175438, I would want 175499, etc.

If the numbers were always three digit, I could just grab the first digit and add 99.
NEW_NUMBER=${OLD_NUMBER:0:1}'99'

I guess what I would want to do is to just remove the last two chars and replace with 99.
NEW_NUMBER=${OLD_NUMBER:0:-2}'99'

Does that look right??

LMHmedchem

Longhand using OSX 10.7.5, default bash terminal...

Code:

Last login: Fri Sep  5 20:24:17 on ttys000
AMIGA:barrywalker~> x=1234567
AMIGA:barrywalker~> y=99
AMIGA:barrywalker~> z=${x:0:$((${#x}-2))}$y
AMIGA:barrywalker~> echo $z
1234599
AMIGA:barrywalker~> _

A minor nitpick - suppose your number is 123499. wisecrackers code will return 123499. Is that the NEXT larger number ending in 99, after 123499? You get to decide.

This kind of thing is sometimes called an edge condition.

BTW wisecracker, nice effort.

Try

Code:

num=174
echo $(((num/100+1)*100-1))

scrutinizer's code - good but with the same problem it looks like....

What I am getting at is: problem as stated requires the addition of 1 to the starting number.

Crude example:

Code:

num=199
num=$(( $num + 1 ))
echo $(((num/100+1)*100-1))

That could be remedied like this:

Code:

echo $((((num+1)/100+1)*100-1))

@scrutinizer - absolutely, but I'm trying to get the OP to see your point.