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Replacing punctuation marks with the help of sed

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# 1  
Old 08-27-2014
Replacing punctuation marks with the help of sed
Code:
#!/bin/bash


a=(*.pdf)

punct=((~`!@#$%^&*()_-+=|\[]{};':",./<>?))

for (( i =0; i < ${#a[i]}; i++ ))
do
sed -ri 's/$punct//g' ${a[i]}
done

I cannot use the above code, can you help me in removing all punctuation marks from file name except file extension. The idea is that once all punctuation are removed then [pdf] can be appended with [.pdf] to save the extensions.
# 2  
Old 08-27-2014
Hello Ambijat,

Please find attached the example for removing the punctuations in lines.

Code:
echo "A~\`\!@BCDEFGH" | sed 's/[[:punct:]]//g'

Output will be as follows. You can take referance from same example and then apply in your code.

Code:
ABCDEFGH


Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
ambijat
# 3  
Old 08-27-2014
If you want to verify before running the code, comment the mv part and include echo "{j}"
Code:
for i in *.pdf
do
 FNAME=${i%.*}
 EXTN=${i##*.}
 BNAME=$(tr -dc '[:alnum:]' <<<${FNAME})
 j="${BNAME}.${EXTN}"
 mv "${i}" "${j}"
done

This User Gave Thanks to SriniShoo For This Post:
ambijat
# 4  
Old 08-27-2014
Quote:
Originally Posted by RavinderSingh13
Hello Ambijat,

Please find attached the example for removing the punctuations in lines.

Code:
echo "A~\`\!@BCDEFGH" | sed 's/[[:punct:]]//g'

Output will be as follows. You can take referance from same example and then apply in your code.

Code:
ABCDEFGH

Thanks,
R. Singh
Thanks! RavinderSingh, but could you please explain the echo part--- fairly a novice on that.
Rgs!

---------- Post updated at 11:29 AM ---------- Previous update was at 11:25 AM ----------

Quote:
Originally Posted by SriniShoo
If you want to verify before running the code, comment the mv part and include echo "{j}"
Code:
for i in *.pdf
do
 FNAME=${i%.*}
 EXTN=${i##*.}
 BNAME=$(tr -dc '[:alnum:]' <<<${FNAME})
 j="${BNAME}.${EXTN}"
 mv "${i}" "${j}"
done

Thanks! Srini but a bit tough to follow-- what you mean comment on mv... and what does this <<< mean. I will grateful to you for your explanation on these.

Oh does it mean adding # before mv and put echo to see output in terminal ! Yes thanks I got it if that is the case.
rgs!
# 5  
Old 08-27-2014
Hello ambijat,

echo is having text which has punctuation in it, as per your request you need to remove the punctuation in a string so I have taken an example of same string.
Then in sed part I have used s/ which tells sed to perform substitute operation, then I have used [[:punct:]] which will substitute all punctuations to s/[[:punct:]]// NONE.
Then at last s/[[:punct:]]//g stands for global, which means that all matching occurrences in the line would be replaced.

kindly let me know if you have any queries. Also please take a look to man sed too.

Thanks,
R. Singh
Last edited by RavinderSingh13; 08-27-2014 at 03:26 AM..
# 6  
Old 08-27-2014
Code:
#!/bin/bash


a=(*.pdf)


for (( i =0; i < ${#a[i]}; i++ ))
do
echo ${a[i]} | sed 's/[[:punct:]]/_/g' | sed -e 's/_.pdf/.pdf/g'

done

Kindly, see I have tried to update it.

---------- Post updated at 11:50 AM ---------- Previous update was at 11:47 AM ----------

Quote:
Originally Posted by ambijat
Code:
#!/bin/bash


a=(*.pdf)


for (( i =0; i < ${#a[i]}; i++ ))
do
echo ${a[i]} | sed 's/[[:punct:]]/_/g' | sed -e 's/_.pdf/.pdf/g'

done

Kindly, see I have tried to update it.
Oh Thanks folks it does the trick my only mistake was to use _.pdf instead of _pdf thanks!

But the task is now how to direct the output to change the filename, can you suggest.

---------- Post updated at 11:57 AM ---------- Previous update was at 11:50 AM ----------

Code:
#!/bin/bash


a=(*.pdf)


for (( i =0; i < ${#a[i]}; i++ ))
do

b=`echo ${a[i]} | sed 's/[[:punct:]]/_/g' | sed -e 's/_pdf/.pdf/g'`

mv ${a[i]} $b
done

This is my final version and it works can you comment on it to make it better. once again thanks
rgs!
# 7  
Old 08-27-2014
Hello ambijat,

Untested but you can try awk also for same.

Code:
echo ${a[i]} | awk '{gsub(/[[:punct:]]/,X,$0); gsub("pdf",".pdf",$0);print $0}'


Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
ambijat
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