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Search for a particular file and then cat its contents

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# 1  
Old 07-27-2014
Search for a particular file and then cat its contents
Hi Friends,

I am looking for a particular file abc* for today's date and then i want to cat its contents to another variable. How to do this. The first step has been accomplished i.e. searching for that file. Now i want to cat the result of this output i.e. abc.txt

Code:
 
 
bash-3.2$ ls -l /folder/abc* -al --time-style=+%D | grep $(date +%D)
-rwxrwxrwx 1 admin admin 401 07/26/14 /folder/abc.txt

# 2  
Old 07-27-2014
@srkmish

Try below one:

Code:
ls -l /folder/abc* -al --time-style=+%D | grep $(date +%D) |awk '{print $7}'| xargs cat

# 3  
Old 07-27-2014
Hey this worked perfectly thanks. Now i want to grep for a string in that file and copy the grepped result into a variable. However, i am not able to do so. What am i doing wrong?

Code:
 
a='ls -l /folder/abc* -al --time-style=+%D | grep $(date +%D) |awk '{print $7}'| xargs cat | grep 'Authentication''
bash: }| xargs cat | grep Authentication: command not found

# 4  
Old 07-27-2014
Srkmish: I'm on vacation and dont have my test machine with me to test the command and give you a perfect one.But I think your using single quote which should be replaced by back quote or $(your command),below is the one may helpful to you :

Code:
a=$(ls -l /folder/abc* -al --time-style=+%D | grep $(date +%D) |awk '{print $7}'| xargs cat | grep 'Authentication')

or
Code:
a=`ls -l /folder/abc* -al --time-style=+%D | grep $(date +%D) |awk '{print $7}'| xargs cat | grep 'Authentication'`

May be helpful to you
# 5  
Old 07-27-2014
Oh yeah, the backquoute works perfect. Thanks Smilie
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