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07-21-2014

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How to search pattern in file?

Hi I want to search pattern in file "S12345678B" which start with S and end with B total length is 10,numeric part 12345678 is variable.
e.g S99001229B and S88226901B.
please help

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Code:

awk '/S[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]B/' file

---------- Post updated at 06:53 AM ---------- Previous update was at 06:50 AM ----------

If you want to print all the words matching the pattern

Code:

awk '{for(i = 1; i <= NF; i++) {if($i ~ /^S[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]B$/) print $i}}' file

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Thanks million

---------- Post updated at 09:30 AM ---------- Previous update was at 06:16 AM ----------

Code:

awk '{for(i = 1; i <= NF; i++) 
{if($i ~ /^S[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]B$/)
 print $i}}'

file,This is not working what is NF?

Last edited by Corona688; 07-21-2014 at 11:59 AM..

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The below code will print all the lines containing the required pattern,

Code:

awk '/S[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]B/{print}' file.txt

Ex:
file.txt
abcS12345678B hidi
ghdgh S87654321B hi
Hi helloo

output:
abcS12345678B hidi
ghdgh S87654321B hi

If you want the pattern to be a word, use the below code,

Code:

awk '/\<S[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]B\>/{print}' file1.txt

Output will be :
ghdgh S87654321B hi

The characters "\<" "\>" are used to search for a word pattern.

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