To split a file in exact half using awk


 
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# 8  
Old 07-21-2014
In a previous thread I have made an observation, but my implementation was not good.
Another trial:
Code:
awk 'NR!=FNR {if (FNR*3>NR) exit; print}' file file

---------- Post updated at 03:09 AM ---------- Previous update was at 02:50 AM ----------

Scru's last sample strips leading spaces with $(echo).
Nice alternatives are
Code:
awk -v h="$(wc -l <file)" 'NR>h/2{exit}1' file

Code:
awk -v h=$(grep -c '^' file) 'NR>h/2{exit}1' file


Last edited by MadeInGermany; 07-21-2014 at 05:30 AM..
This User Gave Thanks to MadeInGermany For This Post:
# 9  
Old 07-21-2014
Nice with the three times. It could also be written as
Code:
awk 'NR==FNR{next} FNR*3>NR{exit}1' file file

-v h="$(wc -l file)" is a nicer alternative to remove the leading space (by awk , rather than shell), although there was no determinable difference in speed..

In testing (using the second result, with file in read cache):
Code:
awk -v h=$(echo $(wc -l <file)) 'NR>h/2{exit}1' file

or
Code:
awk -v h="$(wc -l file)" 'NR>h/2{exit}1' file

Seems to be the fastest solution with 100001 lines..

Code:
$ time awk -v h="$(wc -l file)" 'NR>h/2{exit}1' file > /dev/null
real	0m0.055s
$ time awk 'NR!=FNR {if (FNR*3>NR) exit; print}' file file > /dev/null
real	0m0.113s
$ time awk 'FNR==NR{lines++;next}FNR>lines/2{exit}1' file file >/dev/null
real	0m0.119s
$ time awk 'FNR==NR{lines++;next}FNR<=lines/2' file file >/dev/null
real	0m0.150s
$ time awk '{x[++xc] = $0}END{for(i = 1; i <= xc/2; i++) print x[i]}' file > /dev/null
real	0m0.204s
$ time awk '{i=NR/2} i in A{print A[i]; delete A[i]}{A[NR]=$0}' file > /dev/null
real	0m0.310s
$ time awk -F"\n" -v OFS="\n" '{X=X$0"\n"}END{$0=X;NF=NR/2;print}' file > /dev/null
real	0m11.353s

The latter did not seem to work properly with BSD awk, since it produced 10,002 lines (an additional line due to an extra newline) and in mawk it produced mawk: program limit exceeded: maximum number of fields size=32767

With gawk though it worked really well though:
Code:
$ time gawk -F"\n" -v OFS="\n" '{X=X$0"\n"}END{$0=X;NF=NR/2;print}' file > /dev/null
real	0m0.067s

As is most often the case, mawk was fastest:
Code:
$ time mawk -v h="$(wc -l file)" 'NR>h/2{exit}1' file > /dev/null
real	0m0.021s

In fact when using mawk, it became less relevant, since it performed so fast that there was a negligible difference between the fastest solutions
gawk 4 (which uses some of the techniques of mawk) now also often performs better than gawk 3 and BSD awk..

---
In one table:

BSD awkmawkgawk3gawk4Solution
0.0550.0200.0710.029awk -v h="$(wc -l file)" 'NR>h/2{exit}1' file
0.1170.0230.1100.043awk 'NR!=FNR {if (FNR*3>NR) exit; print}' file file
0.1170.0250.2000.051awk 'FNR==NR{lines++;next}FNR>lines/2{exit}1' file file
0.1440.0260.2290.060awk 'FNR==NR{lines++;next}FNR<=lines/2' file file
0.1590.0310.2440.143awk '{x[++xc] = $0}END{for(i = 1; i <= xc/2; i++) print x[i]}' file
0.3450.1800.4190.213awk '{i=NR/2} i in A{print A[i]; delete A[i]}{A[NR]=$0}' file
11.54 (wrong)ERR0.1520.065awk '-F\n' -v 'OFS=\n' '{X=X$0"\n"}END{$0=X;NF=NR/2;print}' file

The measurements were with files cached, so in reality, solutions that read the file more than once will take longer with uncached files...



--
Tests performed on OSX 10.9.4 - BSD awk 20070501, mawk 1.3.4, gawk 3.1.8, gawk 4.0.2

Last edited by Scrutinizer; 07-21-2014 at 09:00 AM..
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