Shell Programming and Scripting

Hi All,
is there any way we can get the job names running with particular owner.

Example: i want to get the job names running with owner as "autosys"

I'm not sure that I understand the question given such little information.

You want to schedule jobs with a particular 'owner'. So this owner must be an account on the system.

You could then schedule jobs using cron or autosys to run under your chosen account.

More information please. Also, what operating system are we talking?

(Or have I completely misunderstood the question?)

Auosys is job scheduling tool provided by CA. I want to get the job names running in autosys with owner: autosys

Yes, don't you just use the directive

Code:

owner:<username>

in Autosys

but the autosys account must exist on the system first.

Yes autosys is installed.

---------- Post updated at 02:12 AM ---------- Previous update was at 02:07 AM ----------

For example: there arr around 1000 jobs like below; i have taken these job definition is a file say

Code:

/tmp/a.txt

Code:

insert_job: job_A   job_type: c
command: echo "this is test"
machine: abc
owner: autosys
permission: gx,wx
date_conditions: 1
days_of_week: all
start_times: "18:00, 08:00"
alarm_if_fail: 1
timezone: UTC

I want to list out

Code:

insert_job and owner

from the above where owner is autosys

So the question is that you have circa 1,000 files (in the same directory?) and you want a script to extract two lines from each and create a report?

(I thought you were talking about modifying Autosys to behave differently).

Yes Hicks. i have the above lines in

Code:

/tmp/a.txt

file
And, want to extract two line where owner=autosys