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If && command giving wrong output

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# 1  
Old 07-07-2014
If && command giving wrong output
Hi All,

I am trying to run a script which will search for 2 strings(stopped,started) in a text file and echo an output depending on below condition

Code:
 
-bash-3.2$ cat trial1.txt
v
ggg
f

Code:
 
-bash-3.2$ cat trial1.sh
VAR9=` grep 'stopped' /tmp/trial1.txt`
VAR10=` grep 'started' /tmp/trial1.txt`
if [ -n $VAR9 ] && [ -z $VAR10 ]
then
    echo "No"
else
   echo "Yes"
fi

The above code should echo "Yes" as VAR9 is definitely null. But it is echoing no.

Please help!
# 2  
Old 07-07-2014
if [ -n ] is evaluated to true - either quote your variables, or use [[ ... ]] instead.

Code:
if [ -n "$VAR9" ] && [ -z "$VAR10" ]

# 3  
Old 07-07-2014
Not directly related to the question, but an alternative is to use grep's return code:
Code:
if grep -q stopped /tmp/trial1.txt && ! grep -q started /tmp/trial1.txt
then

This User Gave Thanks to Scrutinizer For This Post:
rbatte1
# 4  
Old 07-07-2014
This alternative processes the input file only once:
Code:
awk '/stopped/ {++stopped} /started/ {++started} END {if (stopped && ! started) exit 1}' /tmp/trial1.txt
if [ $? -eq 1 ]
then

# 5  
Old 07-08-2014
Thanks guys, all the answers helped.
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