Parsing input paramter in a script


 
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# 1  
Old 02-01-2006
Parsing input paramter in a script

Hi folks I am having a little trouble in parsing a variable read into a ksh script

I have a bunch of variables passed into script

test.ksh HOST SERVER JOB1 JOB2 JOB3 JOB4 JOB5

What I want to do is read all the $JOB variables ($JOB1, $JOB2, $JOB3) into a variable and then read that variable in a loop and use the values in a case statement for further use however when I try doing this

if [ $# -lt 3 ]
then
echo
usage()
echo
exit
fi

J=$3,$4,$5,$6,$7,$8
for JOB in $J
do
case $JOB in
BUPD ) echo $JOB ;;
FUPD ) echo $JOB ;;
DMMD ) echo $JOB ;;
BNMD ) echo $JOB ;;
OC10 ) echo $JOB ;;
WRPF ) echo $JOB ;;
STRT ) echo $JOB ;;
CKPS ) echo $JOB ;;
CKRT ) echo $JOB ;;
esac
done

This however is reading all the variables in one

echo $JOB is returing BUPD,FUPD,DMMD,BNMD,OC10,STRT

Can someone help
# 2  
Old 02-01-2006
Prior to your "for" statement add this line:
typeset IFS=","
# 3  
Old 02-01-2006
Thanks tmarikle!!

It worked
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