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Pivot using awk

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# 1  
Old 06-20-2014
Pivot using awk
Hi,

I am writing a code to basically pivot the data.

Quote:
Input Format
V1 : Value1
V2 : Value2
V3 : Value3
V4 : Value4
V5 : Value5

Required Output Format
Value1|Value2|Value3|Value4|Value5
Code:
awk -v var1="" -v var2="" -v var3="" -v var4="" -v var5="" -v Disp=0\
'BEGIN {FS=":"; OFS="|";}\
/^Pattern1/ {var1=$2;Disp=0;} \
/^Pattern2/ {var2=$2;} \
/^Pattern3/ {var3=$2;} \
/^Pattern4/ {var4=$2;} \
/^Pattern5/ {var5=$2;Disp=1;} \
{
print "$var1,$var2,$var3,$var4,$var5"
}' "InputFile" "OutputFile"

But I am getting the below issues
a) $2 is picking the entire record
b) print statement is displaying result as below
Quote:
Value1|Value1|Value1|Value1|Value1
Value2|Value2|Value2|Value2|Value2
Value3|Value3|Value3|Value3|Value3
Value4|Value4|Value4|Value4|Value4
Value5|Value5|Value5|Value5|Value5
c) How can we remove leading and trailing spaces of Value1... Value5
# 2  
Old 06-20-2014
  1. awk != perl
  2. var != $var
# 3  
Old 06-20-2014
Can't you use something simple like:
Code:
awk '{print $NF}' file | paste -sd \| -

Or is the output not always one line? Are your sample representative for your actual input and output ?
# 4  
Old 06-20-2014
Try also
Code:
awk '{OUT=OUT DELIM $NF; DELIM="|"} END {print OUT}' file
Value1|Value2|Value3|Value4|Value5

# 5  
Old 06-21-2014
and this ???

Code:
 awk -F"[: ]" 'BEGIN{ORS="|";}{print $NF}' file

# 6  
Old 06-21-2014
Quote:
Originally Posted by protocomm
and this ???

Code:
 awk -F"[: ]" 'BEGIN{ORS="|";}{print $NF}' file

That works too, but the problem is that the last character is a pipe symbol instead of a newline.
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