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Script to change password in UNIX

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# 1  
Old 06-17-2014
Script to change password in UNIX
Hi Friends,

Every morning i need to change the password, please advise how it can be automated. I am having pre planned password list for 4 months which can be used as input file for new passwords.

Thanks
# 2  
Old 06-17-2014
Not much information to work with... Please read here.
This User Gave Thanks to DukeNuke2 For This Post:
MadeInGermany
# 3  
Old 06-17-2014
1. Every morning i have login to a user account by ssh and change the password.
2. I am having all list of passwords that i will be using and already provided to user for next 4 months.
3. i can make a cron job which will run every morning to change the password.
4. Also want to add if the password is changed successfully than it should send an e-mail.

One of of doing that comes to my mind is use password expire and than use echo to change password but it is not working at all....
# 4  
Old 06-17-2014
If you have to do this, which is sounds like is the case, then I suggest you maintain the list of password as hashed/encrypted passwords. That's not hard since you are presumably generating them in advance manually. Once you have that you can change them with "usermod". The "-p" flag will let you pass in a hashed password.

Exposing hashed password strings in the process table isn't ideal, but they aren't usable as is. If someone found them out they would still have to crack the password before they could be used.

Check "man usermod" for the gory details.
# 5  
Old 06-17-2014
How about this - Start with a file called pass.plain with 366 daily passwords in it.

Now encrypt the file like this (be sure to store the plain passwords in a secure location)
Code:
$ while read pass
do
   openssl passwd "$pass"
done < pass.plain > pass.enc

Now in your cronjob you can use the current year's day number (as returned by date +%j) to fetch a password and change users account like this:

Code:
usermod -p $(sed -n $(date +%j)p /var/lib/pass.enc) && mail -s "User password chaged OK" rajjev@company.com <<EOF
    The user password has been changed
EOF

Last edited by Chubler_XL; 06-17-2014 at 11:13 PM.. Reason: No need to specify salt value openssl picks a random one anyway
This User Gave Thanks to Chubler_XL For This Post:
rbatte1
# 6  
Old 06-18-2014
I was having problem in ur program so sharing my code, dont know how to get test123 password from dateout.txt...also i want to send on the e-mail all the option that can happend while password change e.g successully or permission denied etc

Code:
!/bin/sh
CWD=/home/raj/Password
cd $CWD
rm result
(grep "`date +"%d-%b"`" file.txt) > /home/raj/Password/dateout.txt
if [ -s /home/home/raj/Password/dateout.txt ] 
then 
passwd --expire raj #EXPIRING THE PASSWORD
echo -e "test123\test123" | (passwd raj) >> /home/raj/Password/out.log #SETTING THE NEW PASSWORD FROM DATEOUT
else
echo "File Empty"
fi
egrep -i '(Permission)|(successfully)' > /home/raj/Password/result
if [ -s /home/raj/Password/result ] 
then
MAILTO="abc@abc.com"
CONTENT="/home/raj/Password/result"
(
echo "Subject: Password Change Status "
echo "MIME-Version: 1.0"
echo "Content-Type: text/html"
echo "Content-Disposition: inline"
cat $CONTENT
) | /usr/sbin/sendmail -t $MAILTO
else
echo "bbb"
fi

Last edited by rajjev_saini123; 06-18-2014 at 12:25 PM..
# 7  
Old 06-18-2014
Well, what does dateout look like?
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