Passing arguments to a bash script


 
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# 8  
Old 06-11-2014
You keep changing your post while I'm trying to respond to it...

If the code:
Code:
#!/bin/bash
awk -F "," -vmytable="${1}" '{
a = "CREATE TABLE " mytable "(x int, y string)";
}' file1.txt file2.txt

is working for you, a much simpler and much faster script will produce the same output:
Code:

Yes. That is an empty file. It will produce the same output as your awk script (as long as file1.txt and file2.txt are readable text files.
# 9  
Old 06-11-2014
Hi,

In my bash script using awk i'm achieving many things and my requirement was different where i wanted to pass the tables names through the command promt. And once i create the table ,i'm using that for different purpose and above post i have not shown rest of the code.

Whatever you suggested is really good and time saving but i'm not using that because my other requirements are different.

Thanks,
Shree
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