Shell Programming and Scripting

@akshay

How can I redirect value of say only one variable s1 into a file say s1.txt.

Code:

printf "'%d',",s1 >> s1.txt

But I am getting an error Illegal Statement.

I have used backticks but no success. Can you help me with that ?

Code:

printf "%d, ",s1 >>"s1.txt"

Please give us some context. Are you giving this command to the shell? If that is what you're doing, you want something like:

Code:

printf "'%d'," "$s1" >> s1.txt

Are you using this command in an action clause in an awk script? If that is what you're doing, Akshay already showed you how to do that. (Although he removed the single quotes you seem to want displayed around the numeric quantity that you're printing and added a space to the output after the comma. And if this is part of an awk script that is not read from a file using awk -f awk_script, you can't print single quotes that way unless you play lots of games with the way you give the rest of the script to your shell.)

Sorry for late reply. Was very busy.

This solves my Problem. Thanks

Do you have idea about how can I write a multi-line regular expression ?

like say for example,

Code:

17,9:10/8013765024
,10:1
,11:1
23,9:1235455
,11:5

Now I need a regular expression which will help me extract the value for first 11 i.e. 1 and not the value of second 11 i.e. 5.

So, I need to make a regular expression like,

Code:

17[,0-9]*[\n]*,11:

But this doesn't work.
I have tried tweaking it but was not successful.
Also, Is there a better way to do this like using awk ?

---------- Post updated at 11:15 AM ---------- Previous update was at 11:14 AM ----------

The basic idea is to find the value of 17..,11: which in the above case is 1 and replace it with another value say 2.