Shell Programming and Scripting

I'm writing a UNIX script to interpret text files and search for certain strings to output and need to delete certain lines that contain characters that I would like removed from the file. The rest of the script is already completed and I have it output how I would like, but I cannot seem to get this part to work how I want it to.

I would like the program to delete the next 10 lines after the phrase "12: " (with the space, but without the quotations) appears. I currently have written

Code:

sed 'Re: /d'

, but that doesn't seem to work; I just get the error message "sed: can't read /Re: /d: No such file or directory" when trying to run the script on a file.

If you could explain to me how to delete a line containing that string or, better yet, how to delete that line followed by the next 10 lines, it would be much appreciated.

Welcome to forums, you can try something like this if you have awk

Code:

$ awk '/pattern_to_search/{s = FNR+10}FNR>=s' file

if this doesn't work then please provide sample input.

Have a look at your manual page for grep If it supports the -A flag, then that may do just what you need.


Robin