Shell Programming and Scripting

for i in * ; do (cd $i && echo $i && /test1/execute/testb);done

for file in `ls *.txt`
do
if [ ! "$file" = "$Z" ] && [ ! "$file" = "$Z2" ] && [ ! "$file" = "$Z3" ] && [ ! "$file" = "$Z4" ] &&
[ ! "$file" = "$Z5" ] && [ ! "$file" = "$Z6" ] ; then echo "NO"; break 1;
else
echo "it is there"
fi
done

ls "$Z" "$Z2" "$Z3" "$Z4" "$Z5" "$Z6" && echo "it is there" || echo "NO"

for searchfile in $Z $Z2 $Z3 $Z4 $Z5 $Z6
do
   if [ -f $searchfile ]
   then
      echo "$searchfile is in $PWD"
   fi
fi

find /start/directory -name $Z -o -name $Z2 -o -name $Z3 -o -name $Z4 -o -name $Z5 -o -name $Z6

for i in *
do
   echo $i
   for f in "$Z" "$Z1" "$Z2" "$Z3" "$Z4" "$Z5" "$Z6"
   do
      if [ -f "$i/$f" ]
      then
          echo "it is there"
          continue 2
      fi
    done
    echo "NO"
done

DATEN=$(perl -e 'print scalar(localtime(time -  0 * 24 * 60 * 60)), "\n";' |awk '{print $2,$3,$5}')
DATE1=$(perl -e 'print scalar(localtime(time - 1 * 24 * 60 * 60)), "\n";' |awk '{print $2,$3,$5}')
DATE2=$(perl -e 'print scalar(localtime(time - 2 * 24 * 60 * 60)), "\n";' |awk '{print $2,$3,$5}')
DATE3=$(perl -e 'print scalar(localtime(time - 3 * 24 * 60 * 60)), "\n";' |awk '{print $2,$3,$5}')
for i in * ; do (cd $i; echo $i; for f in `ls *.txt`;
do
file=$(truss -vlstat -tlstat ls -l $f 2>&1 |awk 'NR==4'|gawk '{print $3, $4, $7}')
if [ ! "$file" = "$DATEN" ] && [ ! "$file" = "$DATE2" ] && [ ! "$file" = "$DATE3" ]; then
echo "$file" "the file is not correct" >/dev/null
else echo "IT is OK"
fi
done)
done