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Substitute variable inside nawk

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# 1  
Old 05-27-2014
Substitute variable inside nawk
Hi,

I need to set "prd" in the below command to a unix variable

Code:
nawk '/^#/ {next} FNR==NR {prd[$0];next} !($0 in prd)'

So, this is what i did

Code:
fname=prd   // unix shell variable

nawk -v fname=$fname '/^#/ {next} FNR==NR {fname[$0];next} !($0 in fname)'

But the value of fname i.e "prd" is not getting substituted in the command.

Can you tell me why ?

Code:
OS: SunOS mymac 5.10 Generic_150400-09 sun4v sparc SUNW,SPARC-Enterprise-T5220

# 2  
Old 05-27-2014
Quote:
Originally Posted by mohtashims
Hi,

I need to set "prd" in the below command to a unix variable

Code:
nawk '/^#/ {next} FNR==NR {prd[$0];next} !($0 in prd)'

So, this is what i did

Code:
fname=prd   // unix shell variable

nawk -v fname=$fname '/^#/ {next} FNR==NR {fname[$0];next} !($0 in fname)'

But the value of fname i.e "prd" is not getting substituted in the command.

Can you tell me why ?

Code:
OS: SunOS mymac 5.10 Generic_150400-09 sun4v sparc SUNW,SPARC-Enterprise-T5220

You have 2 variables called 'fname':
  1. Scalar fname passed into awk by: -v fname=$fname
  2. Array fname you're populating with $0: fname[$0]
What's the purpose of passing a scalar fname to awk?
What exactly are you after?
# 3  
Old 05-28-2014
Quote:
Originally Posted by vgersh99
You have 2 variables called 'fname':
  1. Scalar fname passed into awk by: -v fname=$fname
  2. Array fname you're populating with $0: fname[$0]
What's the purpose of passing a scalar fname to awk?
What exactly are you after?
As i explained in the OP all i want is instead of using "prd" in the command i wish to use unix variable fname.

So, the problem is the below is not working !!
  1. Scalar fname passed into awk by: -v fname=$fname
Can you now help ?
# 4  
Old 05-28-2014
Quote:
Originally Posted by mohtashims
As i explained in the OP all i want is instead of using "prd" in the command i wish to use unix variable fname.

So, the problem is the below is not working !!
  1. Scalar fname passed into awk by: -v fname=$fname
Can you now help ?
Maybe this will show you some light

Code:
echo 'Show me the content of $fname' | awk -v fname=$fname '{print fname}'

If you can see prd in your stdout, then that's not the problem.
# 5  
Old 05-28-2014
Hammer & Screwdriver
Let me rephrase my question.

I am using the below code to find the difference between two files prod.properties and back.properties.

Code:
nawk '/^#/ {next} NR==FNR {prod[$0]=$0;next} {if ($0 in prod) { delete prod[$0] } else {print }}; END {for (i in prod) print prod[i]}' prod.properties back.properties

Source: https://www.unix.com/302903183-post5.html

Now, the requirement is to automate the above code so that it does the job for any two file names not neccessarily prod.properties and back.properties

I am passing any two filenames like this.

Code:
./check.sh filename1.properties filename2.txt

and reading them in variables file1=$1, file2=$2.

So, how can I achieve that ?
# 6  
Old 05-28-2014
Assuming that check.sh contains:
Code:
nawk '/^#/ {next} NR==FNR {prod[$0]=$0;next} {if ($0 in prod) { delete prod[$0] } else {print }}; END {for (i in prod) print prod[i]}' prod.properties back.properties

change it to:
Code:
file1="$1"
file2="$2"
nawk '/^#/ {next} NR==FNR {prod[$0]=$0;next} {if ($0 in prod) { delete prod[$0] } else {print }}; END {for (i in prod) print prod[i]}' "$file1" "$file2"

or just:
Code:
nawk '/^#/ {next} NR==FNR {prod[$0]=$0;next} {if ($0 in prod) { delete prod[$0] } else {print }}; END {for (i in prod) print prod[i]}' "$1" "$2"

or even:
Code:
nawk '/^#/ {next} NR==FNR {prod[$0]=$0;next} {if ($0 in prod) { delete prod[$0] } else {print }}; END {for (i in prod) print prod[i]}' "$@"

Last edited by Don Cragun; 05-28-2014 at 06:52 AM.. Reason: Fix typos in file operands add additional option.
# 7  
Old 05-28-2014
So the "prod" inside nawk is just a variable ?

I thought it has some relation with the prod.properties

Please confirm.
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