Shell Programming and Scripting

Hi,

I want to put script. The script is to show file that larger than 100MB include current date (eg: today date).

After find the date, it will compress list file and split the tar.gz file. Any idea how to do that?

This bash script will run auto everyday. It's will transfer will to other server. Please assist me.

Thanks.

What have you tried so far?

Using this command:

Code:

RESULT=`du -sm /mnt/* | awk '{ if ($1 > 100)print $2 }'`

But that show only big file. I want to include a date. Today date. When it's run tomorrow, it will put tomorrow date.

There is a command named date that can help you with that.

e.g.
date "+%F" would display YYYY-MM-DD
It has many other possibilities.

There is also a command named find that might be helpful to find those large files

e.g.

Code:

find /mnt/ -type f -size +10M

That would traverse the /mnt directory and would pick files larger than 10M
It has many other possibilities.

Do i need to put like this:

Code:

`du -sm /mnt/* | awk '{ if ($1 > 100)print $2 }' date "+%F"`

I am afraid that would not make any sense.

Where would you like the date to be? Can you show an example of what you are trying to do?
du -sm /mnt/* | awk '{if ($1 > 100) print $2) }' will produce a column list.

I want to pick date. The current date. As previous i already explain.