Print lines before after pattern meacted


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# 1  
Print lines before after pattern meacted

Hi All,

Am trying to print pervious lines of the pattern matched, I was able to print pattern matched and the required data but don't know how to get the pervious line.


Code:
 ifconfig -a | grep  10.118.67.33 | sed -e 's/^[[: :]]*//' -e 's/[[: :]]*$//' | awk '{FS=" "; print $6}'

output I get is the ipaddress ie,
Code:
 10.118.67.33

what am looking is how to get the pervious line of this ipaddress... can someone please help me on this.


Many thanks
Ops
# 2  
The whole line before pattern?

Code:
ifconfig -a | awk '{a[++i]=$0;} /10.118.67.33/{print a[NR-1]}'

This User Gave Thanks to Aia For This Post:
# 3  
Thanks Aia. logic works perfectly. this what I was looking for and I was struggling to get pervious whole line.

Many Thank Again.
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