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Shell Programming and Scripting

To execute scripts parallelly

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# 8  
Old 05-18-2014
Ok so something like this is can add right

Code:
  wait
if [[ -f $script1.completed && -f $script2.completed ]]
then 
proceed 

done < script1.txt 3<script2.txt

# 9  
Old 05-18-2014
Well. Proceed is the default, so it would be a loop break, rather than proceed, something like
Code:
[[ -f "$script1.completed" && -f "$script2.completed" ]] || break

# 10  
Old 05-18-2014
Ok fine how to add the name like $script1.completed becoz in my file i will have 1.sh so it should read as 1.completed rather than 1.sh.completed since the loop will hold $script1 assigned as 1.sh
# 11  
Old 05-18-2014
Either change the name of the completed flag or try something like parameter expansion, "${script1%.sh}.completed"
Last edited by Scrutinizer; 05-18-2014 at 07:18 AM..
# 12  
Old 05-18-2014
I can't change the flag its the standard flag maintained but variable extension will not be touched as the flag it will 1.completed or 1_1.completed. So need to check the file with $script1.completed by taking the basename of the $script1 variable

Not getting with the below code i have deleiberity not touching completed flag in 1_1 script but rest of the set is getting executed. Considering in my script files i am not having .sh extensions

Code:
hile read script1 && read script2 <&3
do
  "./$script1" &
  "./$script2" &
  wait
[[ -f "${script1%}.completed" && -f "${script2%}.completed" ]] || break
done < s1.txt 3<s2.txt

Last edited by rohit_shinez; 05-18-2014 at 07:23 AM..
# 13  
Old 05-18-2014
Yes that is what I mean, compare:
Code:
$ foo=bar.sh
$ echo "${foo%.sh}.completed"
bar.completed
$

# 14  
Old 05-18-2014
I tried something like this but the next set is running which shouldn't


Code:
while read script1 && read script2 <&3
do
  "./$script1" &
  "./$script2" &
  wait
if [[ ! -f "${script1%}.completed" ||  ! -f "${script2%}.completed" ]]
then
exit 1
fi
done < s1.txt 3<s2.txt
~
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