Shell Programming and Scripting

#Comment1
#Comment2
#Comment3
StartJob
 Job "Job1"
 Date "2014-05-14"
 Column='records
 (
  column1 char(100);
  column2 varchar2(10);
 )'
 ......
 Some rows.....
 ..........
 .........
 Column='records
 (
  column3 date(10);
  column4 varchar2(5);
  column2 varchar2(10);
 )'
EndJob
StartJob
 Job "Job14"
 Date "2014-05-12"
 Column='records
 (
  column1 char(100);
  column16 varchar2(10);
 )'
 ......
 Some rows.....
 ..........
 .........
 Column='records
 (
  column17 date(10);
  column18 varchar2(5);
  column19 varchar2(10);
 )'
EndJob
and so on... many jobs will be there in same file

1) while executing script if I give column1 as search criteria, i should get output based on above file is
Job1
Job14
//Since column1 exists in both the jobs.
1) while executing script if I give column17 as search criteria, i should get output based on above file is
Job14

printf "Enter column name: "
read col

awk -v C="$col" '
        /Job/ {
                J = $2
                gsub ( /"/, X, J )
        }
        $1 == C {
                A[J]
        }
        END {
                for ( k in A )
                        print k
        }
' InputFile.txt