Shell Programming and Scripting

What is the error you are getting? Try:

Code:

....
awk  "$1 ~ /"${!temp_5}"/ {
....
1"   modem5_2_top_aapd_wrapper.prescan.v > temp20.v
....

No. The "$1" above is intended to be a reference to awk's field #1, not parameter #1 to the shell. In double quotes, the shell will expand it before awk sees it. It could be done with:

Code:

...
awk '$1 ~/'"${!temp_5}"'/ {
...
1' modem5_2_top_aapd_wrapper.prescan.v > temp20.v

but it is generally much better to use:

Code:

...
awk -v ere="${!temp_5}" '$1 ~ ere {
...
1' modem5_2_top_aapd_wrapper.prescan.v > temp20.v

as Scrutinizer suggested in message #2 in this thread.

Of course the expansion ${!var} only works with recent versions of bash. That expansion is not in the standards and (as far as I know) is not supported by any other shell. (Recent versions of the Korn shell can do something similar with reference variables, but the syntax is different.) Shell array variables aren't in the standards yet either, but indexed arrays are mostly portable between bash and ksh scripts.