Shell Programming and Scripting

Code:

awk '{n=split ($0,tab)}{for(i=0;i<=n;i++){if(tab[i]=="am") count++}};END{print count}' file

this is shell script or a simple command to find the occurence

Yes it is a command line awk to find occurrence, the difference with script of clx is if there are several "am" in a line, i count it.

With awk, try also

Code:

awk '{n+=gsub(/am/,"&")}END{print n}' file

thanks all i will try and reply if i have any doubts

Code:

tr " " "\n" < input_file | grep -c search_word

You could add a -i flag to the grep if you want it case insensitive.

This will split the words on to separate lines. The search_word should really be explicit so you don't get false matches, e.g. looking for am, you could catch spam. Consider using "^am$" to show the beginning and end of the line. Some versions of grep allow you to specify a whole word match only, and that may help. What OS & version are you running with?

As an example:-

Code:

$ cat infile
I am not spam

$ tr " " "\n" | grep -i "am"
am
spam

$ tr " " "\n" | grep -i "^am$"
am

Robin

actually its centos i am working with... i am new to it but i need to find the occurence of the word "another" from 16000 lines in a log file