Shell Programming and Scripting

hey everybody.
i'm tryiing the whole day to solve my problem.
i have a file with 500 columns and about 20 rows. i just want to build a for-loop using awk, which tests in the first column a condition for each row, then does the command and next goes further to the next column.

so, for example my .txt file looks like:

Code:

1.83   1.48   5.20   9.23
4.92   0.23   6.94   0.01
5.99   8.88   7.92   9.31

now, i want to proof, if the first column has values > variable and if yes, it should create a new file with 1 or 0 at the same place. for example, if the variable is 3, the new file should look like:

Code:

0   0   1   1
1   0   1   0
1   1   1   1

i know, that with

Code:

awk '$1>'$a'' input.txt >> new.txt

i get all the rows of coloumn 1, which are > the variable a.

the problem is the for loop for awk.
i want something like:

Code:

for ((i=1; i<4; i++)) ; do  awk  '{print $'$i' "\n"}' input.txt ; another_command ; done

but the first command prints only column under column and this is not what i need

Code:

awk -v c=3 '{for(i=1;i<=NF;i++) $i=($i<c)?0:1}1' input.txt

thanks a lot vgersh99!!!!!!

Try also:

Code:

awk '{for (i=1; i<=NF; i++) $i=$i>a}1' a=3 file
0 0 1 1
1 0 1 0
1 1 1 1