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Shell Programming and Scripting

Precision in print

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# 1  
Old 04-13-2014
Precision in print
I have a shell script which prints a variable to a text file (sorry if this is the wrong terminology, I'm new to this):
Code:
awk `{sumdiffsqt+=$1;stdevt=sqrt(sumdiffsqt/('${n}'-1));errt=stdevt/sqrt('${n}')} END {print '$period',stdevt,errt}' diffsqt.txt >> ${xstation1}_${xstation2}_tt.err

I need period to have 2 decimal places, but stdevt and errt to have however many they already have. period is defined with two, but only prints to the nearest significant figure, is there any way of changing this?
# 2  
Old 04-13-2014
Try:
Code:
awk -v OFMT="%.2f"  ....

# 3  
Old 04-13-2014
Thanks, but didn't work. Still comes out to the nearest sig. fig.
# 4  
Old 04-13-2014
Try:
Code:
... print '$period'+0,stdevt,errt} ...

It is better to pass shell variables using the -v option..
# 5  
Old 04-13-2014
Thanks for your help! Got it working well now
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