Shell Programming and Scripting

Hi,

I'm using /bin/sh

I would appreciate if someone could help me with SED syntax for a "simple" line.

Here is where I Got to:


I have these strings that are returned by my(Examples) (naturally "FullPath" is always changing don't hardcode this lol)
FullPath/AAA.framework
FullPath/BBB.framework
FullPath/CCC.framework
FullPath/DDD.framework

That I want to convert to
FullPath/AAA.framework/Versions/5/AAA
FullPath/BBB.framework/Versions/5/BBB
FullPath/CCC.framework/Versions/5/CCC
FullPath/DDD.framework/Versions/5/DDD

So basically I want to seach for "anything" after a slash up to the dot and "extract it" to copy it to the end of the string.

I'm banging my head but here is where I got to (feel like I'm near a solution)

Code:

MyFindCommand | sed -e "s/\(.*Framework\)/\1\/Versions\\/5\//"`

Any help would be really appreciated

Regards

Code:

sed -r 's|\/(.*?)\..*|&/Versions/5/\1|g'

You haven't said what OS you're using. The script in2nix4life supplied will work on some systems, but the -r option is not available in all versions of sed. With a standards-conforming sed, the following should work:

Code:

MyFindCommand | sed 's!\(.*/\)\(.*\)\([.]framework\)!\1\2\3/Versions/5/\2!'

Thanks to both of you

Indeed, the -r wasn't available to me (on Mac OsX). Didn't know there were difference, sorry for not posting the OS.

I tried the second solution and it worked for me. Someone else gave me this solution which also worked, not sure which one is better and why but will post in case it help someone.

Code:

 sed 's#/\(.*\)/\(.*\)\.framework$#/\1/\2.framework/Versions/5/\2#g'

I prefered the one from Don Cragun as it seem neater and shorter.

Thanks a lot for your help !