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How to count a number using awk?

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# 1  
Old 03-26-2014
How to count a number using awk?
hi, does any one know how to compare a file1 with many files and have to count a number (i.e. 1) like the following ..Thanx in advance

input

Code:
file1	file2	file3	filen
1	1	1	1
1	1	1	1
1	1	1	1
0	1	1	1
1	0	0	0
1	0	0	0
0	0	0	0
1	0	1	0

output

Code:
instances in file1 only - 2
instances in all files but not file1-1
instances in all files - 3
instances in none - 1

# 2  
Old 03-26-2014
What have you tried?
# 3  
Old 03-26-2014
I am doing some thing like this

Code:
awk '{print $1"_"$2"_"$3"_"$4}' $1 | awk '{h[$1]++}; END { for(k in h) print k, h[k] }' |grep -v file

# 4  
Old 03-26-2014
One way to do it:

instances in file1 only:
Code:
paste file1 file2 file3 file4 | grep -c '^1[^1]*$'

instances in all files but not file1:
Code:
paste file1 file2 file3 file4 | grep -c '^0[^0]*$'

instances in all files:
Code:
paste file1 file2 file3 file4 | grep -c '^[^0]*$'

instances in none:
Code:
paste file1 file2 file3 file4 | grep -c '^[^1]*$'

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