Shell Programming and Scripting

Hi
I am failing to write a script which compares a list of dates in a file with today's date.
OS: Solaris 10
I have a file which has server names & dates, i need to compare the date in this file with today's date, if it is less than today it should print the server name.

code i tried is

Code:

date1=`date +"%m%d%y"`
while read server date2
do
  if [[ "$date2" -le "$date1" ]]
  then
    echo " match"
  else 
    echjo " no match"
  fi
done < file

I am receiving an error for 08 day it says
[[:03/08: value too great for base (error token is "08")

Please help ...

The error message indicates that the shell is trying to convert a string to a number and failing.

-le is a numeric comparison, so the shell is expecting numeric values. You haven't supplied any example input, but the error text is complaining about what looks like a slash-separated date. The shell can't convert that to a number.

Comparing dates like that won't give you valid results anyway (e.g. 280113 is numerically less than 100110) - you'll need something like 'days since', or a more sophisticated comparison.

Try comparing the dates in YYMMDD format then you can compare them directly:

Code:

date1=`date +"%y%m%d"`
sed 's:/: :g' file | while read server month day year
do
  if [[ "$year$month$day" -le "$date1" ]]
  then
    echo " match"
  else
    echo " no match"
  fi
done

Thanks guys !!... that helped me...
i have also tried using " < " while comparing , even this was successfull ...

Thank you so much once again .... !!!!