Shell Programming and Scripting

Hi,


I have all my pictures as *.JPG and *.CR2 in the following folder structure:
/media/a_2TB/pictures/year/year-month-day-hour/picture*.*

But sometimes I added a subdirectory -->
/media/a_2TB/pictures/year/year-month-day-hour/suba/picture*.*
/media/a_2TB/pictures/year/year-month-day-hour/subb/picture*.*


I would like to create symbolic links to all pictures of a whole year.

The following command is working fine except of additional sub-directories.

Code:

find 2006/. \( -name "*.CR2" -o -name "*.JPG" \) -execdir sh -c 'ln -s "$PWD"/$(basename {}) ../../2006_Links/Link_$(basename {})' {} \;

What do I have to change to make it flexible to subfolders?

I tried changing the command but it then it won't work anyhow :-(

Code:

f=$(pwd);
find 2006/. \( -name "*.CR2" -o -name "*.JPG" \) -execdir sh -c 'ln -s "$PWD"/$(basename {}) "$f"/2006_Links/Link_$(basename {})' {} \;

Altough the same command without the path variable does work:

Code:

find 2006/. \( -name "*.CR2" -o -name "*.JPG" \) -execdir sh -c 'ln -s "$PWD"/$(basename {}) /media/a_2TB/pictures/2006_Links/Link_$(basename {})' {} \;

Best regards,
Arthur

try:

Code:

f=$(pwd);
export f
find 2006/. \( -name "*.CR2" -o -name "*.JPG" \) -execdir sh -c 'ln -s "$PWD"/$(basename {}) "$f"/2006_Links/Link_$(basename {})' {} \;

Thank you, Chubler_XL!!!

It works :-)

f is a variable with scope limited to the current process. export f changes the scope to include all descendants of the current process.

The variable is visible to the "grandson": find ... -exec [child of a child]