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Wildcard in bash script

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# 8  
Old 03-02-2014
Perhaps I misread, if the file names have names that exactly match R1??????R2, for example R1abcdefR2 then you would need ^R1......R1$.

If the file names contain more characters than these 10 then you would need a pattern like *R1??????R2* which would correspond to the regular expression R1......R1 .
# 9  
Old 03-02-2014
Thank you.!
if echo "$z" | grep -q *R1??????R2*

works fine, as well!

To clarify: this string is just a part of the filename. There is stuff before and after.

jahn
# 10  
Old 03-02-2014
In that case you could use patterns like this:

Code:
case $z in
   (*R1??????R1*)  echo "$z" 
esac

or

Code:
if [[ "$z" == *R1??????R1* ]]
then
  ...
fi

or if you want to use grep with regex like in post #2:
Code:
if echo "$z" | grep -q "R1......R1";

# 11  
Old 03-02-2014
could? must!
Code:
grep -q *R1??????R2*

takes additional args as files to search in, and ignores stdin.
Last edited by MadeInGermany; 03-02-2014 at 06:51 PM..
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