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Both if and else are not working

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Top Forums Shell Programming and Scripting Both if and else are not working
# 1  
Old 02-28-2014
Both if and else are not working
Hello ,

Below is the code :

Code:
if [ "$targ" = "pref" ]; then
Inst=`$ORACLE_HOME/bin/srvctl status database -d | grep -E "$Avail"|awk '{print ($NF)}'`
echo "Insttest";
if [ "$host = "$Inst" ]; then
Reloc=`$ORACLE_HOME/bin/srvctl relocate service -d $database -s $service -i $Avail -t $Pref -f`
fi
else
Inst=`$ORACLE_HOME/bin/srvctl status database -d | grep -E "$Pref"|awk '{print ($NF)}'`
echo "Insttest";
if [ "$host = "$Inst" ]; then
Reloc=`$ORACLE_HOME/bin/srvctl relocate service -d $database -s $service -i $Pref -t $Avail -f`
fi
fi;;


None of the Insttest is being printed which means that neither if nor else part is being executed.

Please advise.


Best regards,
Vishal
Last edited by Scrutinizer; 02-28-2014 at 11:34 AM.. Reason: Repaired broken code tags
# 2  
Old 02-28-2014
You set a variable named Inst and print the contents of a variable named Insttest. Since you never set Insttest, why would you expect any output (other than blank lines)?
# 3  
Old 02-28-2014
What happens above that code? A runaway here-document might be eating the rest of your program, or you might have missed an exit (or accidentally called a function with exit in it) etc etc.
# 4  
Old 02-28-2014
Take a look at if [ "$host" = "$Inst" ]; then twice...
Last edited by wisecracker; 02-28-2014 at 12:22 PM..
This User Gave Thanks to wisecracker For This Post:
Corona688
# 5  
Old 02-28-2014
If you indent your code, it might make it clearer where the various clauses are. For the first test, if the value of $targ is the string pref or not, you should see the output "Insttest"

Not sure on the trailing ; though.

Code:
if [ "$targ" = "pref" ]; then
   Inst=`$ORACLE_HOME/bin/srvctl status database -d | grep -E "$Avail"|awk '{print ($NF)}'`
   echo "Insttest";
   if [ "$host = "$Inst" ]; then
      Reloc=`$ORACLE_HOME/bin/srvctl relocate service -d $database -s $service -i $Avail -t $Pref -f`
   fi
else
   Inst=`$ORACLE_HOME/bin/srvctl status database -d | grep -E "$Pref"|awk '{print ($NF)}'`
   echo "Insttest";
   if [ "$host = "$Inst" ]; then
      Reloc=`$ORACLE_HOME/bin/srvctl relocate service -d $database -s $service -i $Pref -t $Avail -f`
   fi
fi;;

What do you see?


Robin
# 6  
Old 02-28-2014
Hello,

This is AIX platform.The problem is here that when in the first if condition

Code:
if targ=pref

It is running fine if targ value is pref however if targ=avail it exits from if else.

It appears to me that the statement is failing when it compares as below

Code:
pref(targ)=avail

and even it doesn't go to else and simply go for next service in loop.

Is there a way that we can make string comparison in AIX such that if the strings are not equal in first if then it should go to else part rather showing failure going to the next service in for loop


Best regards,
Vishal
# 7  
Old 02-28-2014
Quote:
Originally Posted by Vishal_dba
Hello,

This is AIX platform.The problem is here that when in the first if condition

Code:
if targ=pref

It is running fine if targ value is pref however if targ=avail it exits from if else.

It appears to me that the statement is failing when it compares as below

Code:
pref(targ)=avail

and even it doesn't go to else and simply go for next service in loop.

Is there a way that we can make string comparison in AIX such that if the strings are not equal in first if then it should go to else part rather showing failure going to the next service in for loop


Best regards,
Vishal
We have pointed out several problems in your code.

Have you made any changes based on our comments?

What shell are you using? What for loop?

Please show us your current code and a trace (set -xv) for this code (so we can see what values are being processed and figure out what branches are being taken).
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