Extract data from file


 
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# 1  
Old 01-16-2006
Extract data from file

Dear All ,
I am posting first time in this forum . Please ignore my mistakes .

I am learning Unix and i need help to extract specific data from file .

1. I want to grep number of fails from log . The file contains "fails" word in line if test cases are failed .

2. The log contains results for different version . i want to count total number of fails on different version .

3. The log contains more than 1000 lines and searching fails is very difficult for me .

Example-
version 10--- passed
vesrion 10 --- fails
version 10 -- passed
version9 -- passed
version9 - fails

please help me to write shell scripting

regards
dips
# 2  
Old 01-16-2006
#!/usr/bin/ksh

IFS="
"

for name in $(grep fails tmp1 | cut -d"-" -f1 | sort -u)
do
echo $name failed $(egrep -c "$name.*fails" tmp1) times
done
# 3  
Old 01-16-2006
it is giving me error . Please help me and write full shell script with example
I am sorry i am in learning stage of unix
waiting for reply
regards
dips
# 4  
Old 01-16-2006
That is complete script, you just need to creat a file with tmp1 contains the data... or have whatever file name you want.

#!/usr/bin/ksh

IFS="
"

for name in $(grep fails <filename> | cut -d"-" -f1 | sort -u)
do
echo $name failed $(egrep -c "$name.*fails" <filename> ) times
done


Replace <filename> with the actual file name.

Also please post the error message when you get any error, otherwise we would not be able to help without knowing the error.
# 5  
Old 01-16-2006
getting error as syntax error at line no 5 : $ unexpected ..

pls help me . ..

Onemorething i have several files . i dont want to hardcord in shell script

please give me soultion
# 6  
Old 01-17-2006
Smilie sirs,

just would like to clarify if the version number and the word version is space delimited or not Smilie

if NOT delimited use this code, save it to a file... use file name as arguments

example:

script.sh filename

Code:
echo "file ${1} contains `grep -c fail ${1}` fails"

for x in `grep fail ${1} | sort -u | cut -f1 -d" "`
do
	echo "version ${x} contains `grep -c fail ${1} | grep -c ${x}` count"
done

if delimited just change cut -f1 -d" " to cut -f2 -d" "

thanks
# 7  
Old 01-17-2006
Sorry it is not working . i am writing my question again in details .

Example
File name :2006-01-17-test-daily-batch-limo.log

The logs conatins 1000 records row by row . if test cases are failed then it prints Fail(s) at end of row .

I want to grep number of fails .

Please help me to grep this ...

waiting for reply thanks in advance
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