How to compare the values of a column in a same file using awk?


 
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# 8  
Old 04-09-2014
Hello,

Following may help too in same.

Code:
awk '{if(f == $1){c=$2 - a}} {f=$1;a=$2} {if(c>50) print $0 OFS "("c")"}' get_differ_check121132

Output will be as follows.

Code:
comp569_c0_seq1 208 (91)
comp569_c0_seq1 328 (120)

NOTE: Where get_differ_check121132 is the input file name.



Thanks,
R. Singh
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DB2_FIELD_NUM(3)							 1							  DB2_FIELD_NUM(3)

db2_field_num - Returns the position of the named column in a result set

SYNOPSIS
int db2_field_num (resource $stmt, mixed $column) DESCRIPTION
Returns the position of the named column in a result set. PARAMETERS
o $stmt - Specifies a statement resource containing a result set. o $column - Specifies the column in the result set. This can either be an integer representing the 0-indexed position of the column, or a string containing the name of the column. RETURN VALUES
Returns an integer containing the 0-indexed position of the named column in the result set. If the specified column does not exist in the result set, db2_field_num(3) returns FALSE. SEE ALSO
db2_field_display_size(3), db2_field_name(3), db2_field_precision(3), db2_field_scale(3), db2_field_type(3), db2_field_width(3). PHP Documentation Group DB2_FIELD_NUM(3)