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How to get date value by variable?

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# 1  
Old 02-13-2014
[Solved] How to get date value by variable?
Hello All,
I have one question:

Code:
> cat abc.txt
BrSp_IVR_Daily_Report_last_day_,date +'%Y-%m-%d',jim,969-PP-A,DAILY,/home/jim/reports/,YES
BrSp_Status_Movements_C_,date +'%Y-%m-%d',jim,969-PP-A,DAILY,/home/jim/reports/,YES

> cat akk.ksh
#!/bin/ksh
get_data()
{
OLDIFS=$IFS
IFS=","

while read fname dfrmt uname serv occr fpath toclient
do
DT=`${dfrmt}`
ssh ${uname}@${serv} -n "ls -lrt ${fpath}${fname}*${DT}*" | awk -F' ' '{print $6"-"$7"-"$8","$5","$NF}' | awk -F/ '{print $1""$NF}' 1>>xyz.txt
done < abc.txt
IFS=$OLDIFS
}
get_data

When I execute akk.ksh it fetches the data, but gives this error..
How cat I get date value in $DT variable?

Code:
date +'%Y-%m-%d': not found [No such file or directory]

I am new to UNIX.
# 2  
Old 02-13-2014
Try this instead:
Code:
#!/bin/ksh
get_data()
{
        while IFS=',' read fname dfrmt uname serv occr fpath toclient
        do
                DT=$($dfrmt)
                ssh ${uname}@${serv} -n "ls -lrt ${fpath}${fname}*${DT}*" | awk -F' ' '{print $6"-"$7"-"$8","$5","$NF}' | awk -F/ '{print $1""$NF}' 1>>xyz.txt
        done < abc.txt
}
get_data

Having IFS set to "," when you issued the command DT=`${dfrmt}` kept the space between "date" and "+'%Y-%m-%d'" from being recognized as a field splitter (so the entire string became a command name instead of date being a command name and +'%Y-%m-%d' being an operand for the date command.
These 2 Users Gave Thanks to Don Cragun For This Post:
Ak1983 rbatte1
# 3  
Old 02-14-2014
Thank you so much Don!!! It worked as I expected..
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