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Top Forums Shell Programming and Scripting Need help in sed command
# 1  
Old 01-13-2014
Need help in sed command
Hi,

I am making script in aix server in ksh shell, i have below mentioned file output
Code:
FILE_ID  COUNT(DISTINCT(X.SRC_STMT_UNIQ_ID))  MAX(X.REC_INSERT_TS)  
  ------------------------------------------------------------------
  BARC5300001201401100000000100180628  180628  10-JAN-2014 23:54:07  
  BARC5300001201401100000000200000283  283  10-JAN-2014 22:59:06  
  BARC5300002201401100000000100035646  35646  10-JAN-2014 22:01:20  
  BARC5300002201401100000000200000276  276  10-JAN-2014 22:26:20  
  BARC5310001201401110000000100000001  80  10-JAN-2014 23:04:21  
  BARC5310002201401110000000100000001  23  10-JAN-2014 22:54:46

In above file BARC53000012014011000000001001
80628 replace with ULKB word and second row BARC53000012014011000000002000
00283 replace with ULKB_sold and third row word with EOD and fourth row word with SOD.


But concern in this every word has format whichis



1) In first row word BARC5300001followed with current date(suppose date today is 10th jan 20140110) and then with 00000001and then any number which is in different color

so word become BARC53000012014011000000001001
80628


i use below sed command in script and i am using one variable which keep track of current date


Code:
 d1= `date  +%Y%m%d`



sed 's/BARC5300001$d10000001*/UKBA'  filenmae

but this pattern search string is not working, i did lots of combination, sometime it searches all row and sometime it only replace part of word like below in each row of file.


Please remember every row word has fixed and differnt format , so please help me in patter search string in one row, so that i will make for another row also.



Code:
UKBA00180628  180628  10-JAN-2014 23:54:07

Last edited by bartus11; 01-13-2014 at 05:59 PM.. Reason: Please use code tags.
# 2  
Old 01-13-2014
Please note that variable expansion never happens inside single quotes or strong quotes.

You should use double quotes or weak quotes instead if you want to perform variable expansion.
# 3  
Old 01-13-2014
Hi Yoda,

i also used below command but it replace part of string not all and also select second row word also which has some part same.
Code:
sed  's/BARC5300001'"$d1"'00000001*/UKBA/g'  filename



and output is like this
Code:
UKBA00180628  180628  10-JAN-2014 23:54:07
 UKBA200000283  283  10-JAN-2014 22:59:06     
BARC5300002201401100000000100035646  35646  10-JAN-2014 22:01:20     
BARC5300002201401100000000200000276  276  10-JAN-2014 22:26:20     
BARC5310001201401110000000100000001  80  10-JAN-2014 23:04:21 
    BARC5310002201401110000000100000001  23  10-JAN-2014 22:54:46

Last edited by pallvi_mahajan; 01-13-2014 at 07:15 PM..
# 4  
Old 01-13-2014
Your requirement is not so clear. But here is something based on assumptions:
Code:
sed 's#BARC.......................#UKBA#' file

# 5  
Old 01-14-2014
I have to second Yoda in that it's very difficult to grasp what you want. Guessing and inferring from your samples, I got this proposal to solve your needs:
Code:
sed "s/BARC5300001${d1}00000001[^ ]*/ULKB/;s/BARC5300001${d1}00000002[^ ]*/ULKB_sold/"  file
  ULKB  180628  10-JAN-2014 23:54:07  
  ULKB_sold  283  10-JAN-2014 22:59:06
. . .

Please adapt to your further needs
# 6  
Old 01-14-2014
hi,

thanks a lot,it solved issue, please explain me for using [^]* at end of pattern matching, bcz when i used only * , pattern matched 2 row word instead of only one matching like ur code did

---------- Post updated at 09:48 AM ---------- Previous update was at 05:05 AM ----------

Hi Rudac,

May you please explain for below ?
# 7  
Old 01-14-2014
man regex:
Quote:
An atom followed by '*' matches a sequence of 0 or more matches of the atom.
In this case, the atom is the bracket expression [^ ]. man regex:
Quote:
A bracket expression is a list of characters enclosed in "[]". It normally matches any single character from the list (but see below). If the list begins with '^', it matches any single character (but see below) not from the rest of the list.
So, you get any rest of your string until a space is hit. If your string is not space delimited, amend the bracket expression or use character classes.
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