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Adding gaps to a string in bash

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# 1  
Old 01-09-2014
Adding gaps to a string in bash
I have the following string, and want to introduce additional spaces between the two %s. This will be done by specifying the gap between the %s. Example having gap=8 will put 8 spaces between the two %s.

Code:
frmt_k1d1_test="%s    %s\n"

I am doing the script in bash.

---------- Post updated at 06:12 AM ---------- Previous update was at 05:42 AM ----------

I have tried this which works. Something simpler would be useful.

Code:
echo "$frmt_k1d1_test" | awk -v g="$gap" 'BEGIN {FS=OFS=""} {for (i=1;i<=NF;i++) {if (i==3) $i=$i g}}1'

# 2  
Old 01-09-2014
Try this
Code:
aLongSpace="                                                                                                            "
gap=8
frmt_k1d1_test="%s${aLongSpace:0:$gap}%s\n"
echo "$frmt_k1d1_test"

# 3  
Old 01-09-2014
Have got another method, however I need to put $gap in the sed statement. How can I pass the gap?

Code:
echo "$frmt_k1d1_test" | sed 's/.../&$gap/g'

---------- Post updated at 06:17 AM ---------- Previous update was at 06:14 AM ----------

Quote:
Originally Posted by chacko193
Try this
Code:
aLongSpace="                                                                                                            "
gap=8
frmt_k1d1_test="%s${aLongSpace:0:$gap}%s\n"
echo "$frmt_k1d1_test"

This works, however I originally have the string

Code:
frmt_k1d1_test="%s    %s\n"

Modification should be done using this string as initial input.
# 4  
Old 01-09-2014
Quote:
Originally Posted by kristinu
Have got another method, however I need to put $gap in the sed statement. How can I pass the gap?

Code:
echo "$frmt_k1d1_test" | sed 's/.../&$gap/g'

---------- Post updated at 06:17 AM ---------- Previous update was at 06:14 AM ----------



This works, however I originally have the string

Code:
frmt_k1d1_test="%s    %s\n"

Modification should be done using this string as initial input.
Just use "" instead of ''
# 5  
Old 01-09-2014
The sed is a good way. However things are not done yet

Code:
echo "$frmt_k1d1_test" | sed "s/.../&$gap/g"

which produces

Code:
%s            %s\    n

---------- Post updated at 06:51 AM ---------- Previous update was at 06:30 AM ----------

I think the best way is to search for 4 spaces, then replace with a string of size gap.
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