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Problem with ssh and checking if file exists

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# 8  
Old 01-09-2014
Quote:
Originally Posted by rbatte1
So are we saying that SSH returns the exit code of the remote command?
Absolutely. ssh is quite sophisticated. It even has separate stdout/stderr streams.
# 9  
Old 01-09-2014
Smilie I feel so ancient. Smilie
# 10  
Old 01-10-2014
Guys, another quick question..

Is it possible to parameterize the directory structure path before passing it to ssh command?

Like Below:

Code:
SHARE_PATH=directory/structure
 
file_avail=`ssh username@host 'if [[ -f "$SHARE_PATH/Daily Report.xls" ]]; then echo 1; else echo 0; fi'`

Apparently the variable $SHARE_PATH is not being read in ssh !

---------- Post updated 01-10-14 at 01:11 AM ---------- Previous update was 01-09-14 at 11:24 PM ----------

Hi, figured out to pass variables to ssh command [Here my file name has spaces]

Below code worked :

Code:
file_name="Daily Report.xls"

file_avail=`ssh username@host "if [[ -f $SHARE_PATH/'$file_name' ]]; then echo 1; else echo 0; fi"`

# 11  
Old 01-10-2014
Yes, you need the correct quotes to prevent your local shell from expanding it before executing the command that opens SSH and invokes the arguments as remote commands.



Robin
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