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sed hash in multiple lines

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# 8  
Old 12-17-2013
Some more:
Code:
awk 'f{print $NF; f=0} /system@remote-server/{f=1}' file

Code:
sed '/system@remote-server/!d;N;s/.* //' file

These 2 Users Gave Thanks to Scrutinizer For This Post:
Hamss RavinderSingh13
# 9  
Old 12-17-2013
Hello Scrutinizer,

Thanks a lot for nice code. Could you please explain the code please.


Thanks,
R. Singh
# 10  
Old 12-17-2013
Sure:
Code:
awk '
  f{                         # if f=1 then (if a match was found previously)
    print $NF                # print the last field
    f=0                      # reset f ( set found is false)
  } 
  /system@remote-server/{    # if a match is found
    f=1                      # then set f to 1
  }
' file


Code:
sed '
  /system@remote-server/!d   # if a match is found then do not delete the line
  N                          # append the next line to the current line
  s/.* //                    # delete everything unto and including the last space
' file

This User Gave Thanks to Scrutinizer For This Post:
Hamss
# 11  
Old 12-17-2013
Quote:
Originally Posted by Hamss
General question; Is it possible to merge multiple regex into one?

E.g. for this case.
We have a this hash and want to make a regex ohny for this pattern 2A:DD:4B:C5:AD:B0:MF:96:51:B0:14:4A:B5:6C:99:FB

So I am increasing the patterns, and merging one into an other:
1. pattern: ([A-Z0-1][A-Z0-1]:) set pattern
2. pattern: ([[A-Z0-1][A-Z0-1]:]*) pattern 1 0-infinite times
3. pattern: ([[A-Z0-1][A-Z0-1]:]*[A-Z0-1][A-Z0-1]) and put the last two chars at the end

Is this possible?
In your hash, I doubt you have :MF:
In general, it's a serie of hex digit.
Your pattern 2 is not pattern 1 0-infinite times, you can simplified your pattern 2 as: ([A-Z0-1:]*)
If you want pattern 1 0-infinite, you can do as: (([A-Z0-1][A-Z0-1]:)*)
And so, pattern 3: (([A-Z0-1][A-Z0-1]:)*[A-Z0-1][A-Z0-1])

And if you want that your pattern is a regex for your hash, the pattern 3 will:
(([0-9A-F][0-9A-F]:)*[0-9A-F][0-9A-F])

Regards.
This User Gave Thanks to disedorgue For This Post:
Hamss
# 12  
Old 12-17-2013
Thank you Scrutinizer for explaination. Here is one more approach for same.

Code:
$ awk '/system@remote-server, Dec 17, 2013, PrivateKeyEntry,/ {getline; gsub(/Certificate fingerprint/, "");print$NF}' file_name
2A:DD:4B:C5:AD:B0:MF:96:51:B0:14:4A:B5:6C:99:FB


Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
Hamss
# 13  
Old 12-18-2013
If you want the regex to match the fingerprint, try:
Code:
sed -rn 's/.*(([A-F0-9]{2}:){15}[A-F0-9]{2})/\1/p' file

This does not necessarily work with all sed versions, and, as pointed out before, it matches HEX numbers only - if you really have sth. like MF in there, adapt the ranges.
This User Gave Thanks to RudiC For This Post:
Hamss
# 14  
Old 12-18-2013
Quote:
Originally Posted by disedorgue
And if you want that your pattern is a regex for your hash, the pattern 3 will:
(([0-9A-F][0-9A-F]:)*[0-9A-F][0-9A-F])
Quote:
Originally Posted by RudiC
If you want the regex to match the fingerprint, try:
Code:
sed -rn 's/.*(([A-F0-9]{2}:){15}[A-F0-9]{2})/\1/p' file

Thanks a lot, that was what I wanted to know Smilie

---------- Post updated at 01:44 PM ---------- Previous update was at 01:39 PM ----------

Quote:
Originally Posted by disedorgue
In your hash, I doubt you have :MF:
Thats actually true. I've changed some digs before posting. Smilie
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